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3 years ago

9

Please help ............plzzzz

1 answer:

N76 [4]3 years ago

6 0

Answer:

1774cm

Explanation:

11x14=154

20x9x9=1620

154+1620=1774

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Please Help!! <br> Thank you!!

egoroff_w [7]

The answer to your question is 3 because when getting the bottom part of the figure you have to make the fractions the same least common denominator, which means the leas common denominator is 6 so you get 7/6 as the area of the figure. Then you multiply that by1/5/6 which is 11/6 and you will get your answer 18/6 = 3. Feel free to ask me any question you need help with.

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3 years ago

Ravi wants to leave a 20% tip on a meal that cost $50. How much money should he leave for the tip?

vampirchik [111]

0.2•50=10 and that is the answer

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3 years ago

What is the value of the digit 9 in the attendance at the redskins vs titan game

Leokris [45]

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3 years ago

Question 1<br> Let f(x) = 2x^2 - 3x - 4 and g(x) = x + 5. Find (fg)(x).

Scilla [17]

The function (fg)(x) is a composite function

The value of the function (fg)(x) is 2x^3 + 7x^2 - 19x - 20

<h3>How to determine the function (fg)(x)?</h3>

The functions are given as:

f(x) = 2x^2 - 3x - 4 and g(x) = x + 5.

To calculate (fg)(x), we make use of

(fg)(x) = f(x) * g(x)

So, we have:

(fg)(x) = (2x^2 - 3x - 4) * (x + 5)

Expand

(fg)(x) = 2x^3 - 3x^2 - 4x + 10x^2 - 15x - 20

Collect like terms

(fg)(x) = 2x^3 - 3x^2 + 10x^2 - 4x - 15x - 20

Evaluate

(fg)(x) = 2x^3 + 7x^2 - 19x - 20

Hence, the function (fg)(x) is 2x^3 + 7x^2 - 19x - 20

Read more about composite function at:

brainly.com/question/10687170

7 0

2 years ago

I need help with this problem. Given: BC = 10 inches AC = √50 inches m∠CBD = 60° m∠CAD = 90° Calculate the exact area of the sha

Nikitich [7]

Answer:

Area of the shaded region = 23.33 in²

Step-by-step explanation:

Area of a sector = $\frac{\theta}{360}(\pi r^{2})$

Where θ = Central angle subtended by an arc

r = radius of the circle

Area of the sector BCD = $\frac{60}{360}(\pi) (10^{2})$

= 52.36 in²

Area of equilateral triangle BCD = $\frac{\sqrt{3} }{4}(\text{Side})^2$

= $\frac{\sqrt{3} }{4}(10)^2$

= $25\sqrt{3}$ in²

= 43.30 in²

Area of the shaded portion in ΔBCD = 52.36 - 43.3

= 9.06 in²

Area of sector CAD = $\frac{90}{360}(\pi)(\sqrt{50})^2$

= 39.27 in²

Area of right triangle CAD = $\frac{1}{2}(\text{Base})(\text{Height})$

= $\frac{1}{2}(\text{AC})(\text{AD})$

= $\frac{1}{2}(\sqrt{50})(\sqrt{50})$

= 25 in²

Area of the shaded part in the ΔACD = 39.27 - 25

= 14.27 in²

Area of the shaded part of the figure = 9.06 + 14.27

= 23.33 in²

8 0

3 years ago