The perimeter of a rectangle is 48 inches. If the length is 2 more than the width, what is the length and width?
2 answers:
2L + 2W = 48
L + W = 24
(W + 7) + W = 24
W = 8.5 inches
L = 15.5 inches
Answers:
Length = 13 inches
Width = 11 inches
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Work Shown:
w = width, some positive number
w+2 = length, since it is 2 inches more than the width
P = perimeter of the rectangle
P = 2(width + length)
P = 2(w + w+2)
P = 2(2w+2)
P = 4w+4
We're told that the perimeter is 48 inches. So we'll set the previous result equal to 48 and solve for w.
P = 48
4w+4 = 48
4w = 48-4
4w = 44
w = 44/4
w = 11
The width is 11 inches.
w+2 = 11+2 = 13
The length is 13 inches.
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Checking the answers:
P = 2(L+W)
P = 2(13+11)
P = 2(24)
P = 48
The answers are confirmed.
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