Answer:
How many of these passwords contain at least one occurrence of at least one of the five special characters?
Answer:
2 2/21
Step-by-step explanation:
11/2 ÷ 2 5/8
= 11/2 ÷ 21/8
= 11/2 × 8/21
= 88/42
= 44/21
= 2 2/21
Hence 11/2÷2 5/8 is 2 2/21
Answer:
672 squared in.
Step-by-step explanation:
first, we're going to find the height of the prism (it's not provided to us)
im using the Pythagorean Therm .
height: 8 in.
(i got lazy)
The solution of log(4x-6)16=4 is x = 2.
