c) Combine 2+3 to get 5. 100-(5x5) equals 100-25. 100-25 is 75. The answer is 75.
d) Combine 2+3 to get 5. Combine 1+4 to get 5, which is 25. The answer is 5.
g) Combine 4+6 to get 10. Combine 70+-6 to get 64. Take the root of 64, leaving you with 10-8. Combine 10 + -8 to get 2. The answer is 2.
h) Combine 5+4 to get 9. Take the root of 36, leaving you with 18 + 6. Combine 18 + 6 to get 24. The answer is 24.
5. [15 + 22 + 53] divided by [12 + 18] = [90] divided by [30] = 3 ribbons each.
6. (4 x 12) + (6 x 8) = 96 total.
Answer:
a) 40.13% probability that a laptop computer can be assembled at this plant in a period of time of less than 19.5 hours.
b) 34.13% probability that a laptop computer can be assembled at this plant in a period of time between 20 hours and 22 hours.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question:

a)Less than 19.5 hours?
This is the pvalue of Z when X = 19.5. So



has a pvalue of 0.4013.
40.13% probability that a laptop computer can be assembled at this plant in a period of time of less than 19.5 hours.
b)Between 20 hours and 22 hours?
This is the pvalue of Z when X = 22 subtracted by the pvalue of Z when X = 20. So
X = 22



has a pvalue of 0.8413
X = 20



has a pvalue of 0.5
0.8413 - 0.5 = 0.3413
34.13% probability that a laptop computer can be assembled at this plant in a period of time between 20 hours and 22 hours.
4/7, because both the numerator and denominator can be divisible by 3.
we can find the answer to this problem by thinking about it logically for a minute:
we know that she assigned "x" homework problems on Monday, so,
x=Monday
we also know that she assigned 13 more problems on Tuesday, so,
13=Tuesday
over the course of the two days she assigned a total of 23 homework problems.
to get the answer of how many problems she assigned on Monday, we have to do the total number of problems she assigned(23) minus the number of problems we know she assigned on Tuesday(13), so,
23-13=10
she assigned 10 problems on Monday.