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3 years ago

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Mike owes his brother $9.55. He borrows $10.75 more from his brother. Which of the following best represents Mike's debt to his

brother?
A B C D +$20.20 -$20.30 -$1.20 +$18.80

2 answers:

Radda [10]3 years ago

8 0

Answer:

C - $20.30

Step-by-step explanation:

-9.55 + (-10.75) = - 20.3

Agata [3.3K]3 years ago

3 0

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A telemarketer sells subscriptions for magazines and receives a commission of 20 % on his sales. How much would his commission b

erastovalidia [21]

The commission of telemarketer will be $75.

Step-by-step explanation:

Given,

Worth of subscription sales = $375

Commission rate = 20%

Amount of commission = 20% of worth of subscription sales

Amount of commission = $\frac{20}{100}*375$

Amount of commission = $0.2*375$

Amount of commission = $75

The commission of telemarketer will be $75.

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3 years ago

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miss Akunina [59]

Answer:

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3 years ago

What is the answer for this (3^56^8)(3^96^10)

sweet-ann [11.9K]

The answer is

3^66483360316461674016

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3 years ago

Please answer this correctly

Lynna [10]

Answer:

75%

Step-by-step explanation:

There is 1 whisker and quartiles 1-3 so:

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3 years ago

The gas law for an ideal gas at absolute temperature T (in kelvins), pressure P (in atmospheres), and volume V (in liters) is PV

JulijaS [17]

Answer:

$\frac{dT}{dt}=3.78^{\circ}K/min$

Step-by-step explanation:

We have to calculate the time derivative of T=PV/nR with P and V variable and n and R constants. This is:

$\frac{dT}{dt} =\frac{d\frac{PV}{nR}}{dt}=\frac{1}{nR}\frac{d(PV)}{dt}$

What we have to do is the derivative of a product:

$\frac{d(PV)}{dt}=P\frac{dV}{dt}+V\frac{dP}{dt}$

Substituting, we have:

$\frac{dT}{dt} =\frac{P\frac{dV}{dt}+V\frac{dP}{dt}}{nR}$

where all these values are given since the time derivatives of P and V are their variation rate, using minutes.

We then substitute everything, noticing that already everything is in the same system of units so they cancel out:

$\frac{dT}{dt}=\frac{P\frac{dV}{dt}+V\frac{dP}{dt}}{nR}=\frac{(8atm)(0.16L/min)+(13L)(0.14atm/min)}{(10mol)(0.0821Latm/mol^{\circ}K)}$

And then just calculate:

$\frac{dT}{dt}=3.78^{\circ}K/min$

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3 years ago