Describe the trend in the scatter plot.
2 answers:
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Check the tree diagram of the problem:
The first ball can be either Red or Blue, the second ball can either be Red or Blue.
The branches represent all possible scenarios.
For example, consider the upper branch, the case when both balls are blue:
The first ball is Blue, probability 5/10, the second ball is Blue, probability 4/9 because now there are 4 left blue balls, and 9 balls in total, after we picked the first blue.
The other branches have the same logic.
The question is not completed so we have 2 cases:
"Find the probability that at least 1 ball was red, given that the first ball was red"
here we add the separate probabilities of (R, R) and (R, B)
P(R,R)+P(R,B)=2/9 + 5/18 = 4/18 +5/18= 9/18=0.5
"Find the probability that at least 1 ball was red, given that the first ball was blue"
probability is P(B, R)=5/18=0.28
The first ball can be either Red or Blue, the second ball can either be Red or Blue.
The branches represent all possible scenarios.
For example, consider the upper branch, the case when both balls are blue:
The first ball is Blue, probability 5/10, the second ball is Blue, probability 4/9 because now there are 4 left blue balls, and 9 balls in total, after we picked the first blue.
The other branches have the same logic.
The question is not completed so we have 2 cases:
"Find the probability that at least 1 ball was red, given that the first ball was red"
here we add the separate probabilities of (R, R) and (R, B)
P(R,R)+P(R,B)=2/9 + 5/18 = 4/18 +5/18= 9/18=0.5
"Find the probability that at least 1 ball was red, given that the first ball was blue"
probability is P(B, R)=5/18=0.28
INFORMATION:
We know that:
- stack of mail consists of 8 bills, 10 letters, and 6 advertisements.
- One piece of mail is drawn at random and put aside. Then a second piece of mail is drawn.
And we must find P (both are letters)
STEP BY STEP EXPLANATION:
To find the probability, we need to know that we have two events. First, when one piece of mail is drawn at random and put aside and, second, when a second piece of mail is drawn.
These two events are dependent. If A and B are dependent events, P(A and B) = P(A) • P(B after A) where P(B after A) is the probability that B occurs after A has occurred.
So, first
- Probability of A (the first piece is letter)
- Probability of B after A
Since A already occurred and one piece of the mail was drawn (a letter), now in total we would have 9 letter and 23 total pieces
Finally, replacing in the initial formula
Finally, the probability would be 0.1630
ANSWER:
P (both are letters) = 0.1630