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Nonamiya [84]
2 years ago
5

Quick Math Problems Plz Help Solve For X (Show Ur Work If U Can)

Mathematics
1 answer:
VARVARA [1.3K]2 years ago
5 0

Answer:

5. 6x^2 - x - 2

6. 9x^2 - 15x + 6\frac{1}{4}

Step-by-step explanation:

5:

  • (x+ \frac{1}{2}) (6x-4)
  • (x)(6x) + (x)(-4) + (\frac{1}{2})(6x)+(\frac{1}{2})(-4)
  • 6x^2 - 4x + 3x - 2
  • 6x^2 - x - 2

6:

  • (3x-\frac{5}{2})^2
  • (3x - \frac{5}{2})(3x - \frac{5}{2})
  • (3x)(3x) + (3x)(\frac{-5}{2}) + (\frac{-5}{2})(3x) + (\frac{-5}{2})(\frac{-5}{2})
  • 9x^2 - \frac{15}{2}x - \frac{15}{2}x + \frac{25}{4}
  • 9x^2 - 15x + \frac{25}{4}
  • 9x^2 - 15x + 6\frac{1}{4}
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(A) Product of -2x^{3}+x-5 and x^{3}-3x-4 is:

(-2x^{3}+x-5)(x^{3}-3x-4)

=-2x^{3}(x^{3}-3x-4)+x(x^{3}-3x-4)-5(x^{3}-3x-4)

=(-2x^{3})(x^{3})+(-2x^{3})(-3x)+(-2x^{3})(-4)+x(x^{3})+(x)(-3x)+(x)(-4)+(-5)(x^{3})+(-5)(-3x)+(-5)(-4)

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=-2x^{6}+7x^{4}+3x^{3}-3x^{2}+11x+20

(B) Yes.

Product of -2x^{3}+x-5 and x^{3}-3x-4 = Product of x^{3}-3x-4 and -2x^{3}+x-5 because multiplication is commutative.

Commutative Property of multiplication says that a.b = b.a.

Thus, multiplication is same irrespective of the order of two numbers.



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