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SCORPION-xisa [38]
3 years ago
11

Milli plans to rent a room for her birthday party for $40. The catering charge is $12 per person but there is no charge for Mill

i's meal since she is the guest of honor. If Milli has $100 to spend on her birthday party, what is the maximum number of friends Milli can invite?
Mathematics
1 answer:
Mrac [35]3 years ago
8 0
This is a 2 part question. 

Milli has $100 to spend and pays for the room first. $100 - $40 = $60 to pay for meals.

Each meal is $12 - how many meals can she buy with $60? 

60 / 12 = 5 meals 

So Milli and 5 friends can be at the party. 

To check: 5($12) + $40 = $100
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3 years ago
Find all the points, if any, where the graph of 12x-5y=0 intersects (x+12)^2+(y-5)^2=169.
WITCHER [35]
I: 12x-5y=0
II:(x+12)^2+(y-5)^2=169

with I:
12x=5y
x=(5/12)y
-> substitute x in II:
((5/12)y+12)^2+(y-5)^2=169
(25/144)y^2+10y+144+y^2-10y+25=169
(25/144)y^2+y^2+10y-10y+144+25=169
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6 0
3 years ago
Read 2 more answers
HELP DUE AT MIDNIGHT TN
White raven [17]

Answer:

102

Step-by-step explanation:

These angles are congruent due to corresponding angles thm

3x + 21 = 6x - 60

3x - 6x = -60 - 21

-3x = -81

x = 27

3x + 21

3(27) + 21

81 + 21

102

8 0
3 years ago
Write an equation to represent the sum modeled in the following number line.
KonstantinChe [14]

Answer:

-6/4

Step-by-step explanation:

-13/4+7/4=

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Step-by-step explanation:

4 0
3 years ago
A research team at Cornell University conducted a study showing that approximately 10% of all businessmen who wear ties wear the
LenKa [72]

Answer:

a) The probability that at least 5 ties are too tight is P=0.0432.

b) The probability that at most 12 ties are too tight is P=1.

Step-by-step explanation:

In this problem, we could represent the proabilities of this events with the Binomial distirbution, with parameter p=0.1 and sample size n=20.

a) We can express the probability that at least 5 ties are too tight as:

P(x\geq5)=1-\sum\limits^4_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\geq5)=1-(0.1216+0.2702+0.2852+0.1901+0.0898)\\\\P(x\geq5)=1-0.9568=0.0432

The probability that at least 5 ties are too tight is P=0.0432.

a) We can express the probability that at most 12 ties are too tight as:

P(x\leq 12)=\sum\limits^{12}_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\leq 12)=0.1216+0.2702+0.2852+0.1901+0.0898+0.0319+0.0089+0.0020+0.0004+0.0001+0.0000+0.0000+0.0000\\\\P(x\leq 12)=1

The probability that at most 12 ties are too tight is P=1.

5 0
3 years ago
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