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Natali [406]
3 years ago
7

Can somebody help me with social studies please?

Mathematics
1 answer:
Nana76 [90]3 years ago
7 0
Sure, what grade are you in and what are the questions about?
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What's the domain of this function graph?<br> A) (-♾, 0)<br> B) (0,♾)<br> C) (-♾,♾)<br> D) (1,♾)
Scilla [17]

Answer:

b) (0,infinity)

Step-by-step explanation:

You can look at the graph and see it starts when x=1, and continues forever in the positive direction.

4 0
3 years ago
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In Game 1, Emerson struck out 30 times in 90 times at bat. In Game 2, he struck out 40 times in 120 times at bat. In Game 3, Eme
VikaD [51]

Answer:

<u>Total number of strikeouts:</u>

  • 30 + 40 + 42 = 112

<u>Total number of at bats:</u>

  • 90 + 120 + 140 = 350

<u>Hits = times - strikeouts:</u>

  • 350 - 112 = 238

<u>Percentage:</u>

  • 238/352*100% = 67.61%

7 0
3 years ago
Ok can someone please help me? 15 pts
Citrus2011 [14]

Answer:

3.2

Step-by-step explanation:

12.8/4 which makes the answer 3.2

7 0
3 years ago
1 point
swat32

Answer:

\log_{10}(147) = 2.1673

Step-by-step explanation:

Given

\log_{10} 3 = 0.4771

\log_{10} 5 = 0.6990

\log_{10} 7= 0.8451

\log_{10} 11 = 1.0414

Required

Evaluate \log_{10}(147)

Expand

\log_{10}(147) = \log_{10}(49 * 3)

Further expand

\log_{10}(147) = \log_{10}(7 * 7 * 3)

Apply product rule of logarithm

\log_{10}(147) = \log_{10}(7) + \log_{10}(7) + \log_{10}(3)

Substitute values for log(7) and log(3)

\log_{10}(147) = 0.8451 + 0.8451 + 0.4771

\log_{10}(147) = 2.1673

3 0
2 years ago
Simplify<br> 7^2x^-3y/49x^-3y^-2
olya-2409 [2.1K]
\frac{7^2x^{-3}}{49x^{-3} y^{-2}} \\ \\  \frac{49x^{-3}y}{49x^{-3}y^{-2}} \\ \\  \frac{49x^{-3}y}{49x^{-3} \times  \frac{1}{y^2} } \\ \\  \frac{49x^{-3}y}{ \frac{49x^{-3}}{y^2} } \\ \\ 49x^{-3} y \times  \frac{y^2}{49x^{-3}} \\ \\  \frac{x^{-3}}{x^{-3}} yy^2 \\ \\ 1 \times yy^2 \\ \\ yy^2 \\ \\ y^3 \\ \\

The answer is: y^3.
4 0
3 years ago
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