Answer:
p = 2
n = 14
m = 3
Step-by-step explanation:
In order to be able combine (either add or subtract) rational expressions we need to write them with a common (similar) denominator. For that reason we first find the Least Common Denominator of both fractions, that way understanding how to express the two fractions using equivalent fractions with like denominator that can be combined.
We see that the denominator of the first fraction contains the factor "x", therefore "x" has to be a factor of that least common denominator.
We also see that the second fraction contains "2" as a factor, therefore 2 has to be a factor as well for our Least Common Denominator (LCD)
So the LCD we need is the product: 2*x which we write as 2x.
Now we write the first fraction as an equivalent one but with denominator "2x" by multiplying top and bottom by 2 (and thus not changing the actual value of the fraction): 
Next we do the same with the second fraction, this time multiplying top and bottom by the factor "x":
Now that both fractions are written showing the same denominator , we can combine them as indicated:
This expression gives as then the values for the requested coefficients.
p = 2
n = 14
m = 3
Answer:
"Starting today, I need to forget what's gone. Appreciate what still remains and look forward to what's coming next."
"Pain makes you stronger, fear makes you braver, heartbreak makes you wiser."
"I will not allow myself to not feel chosen every single day. And I’ll wait till whenever that is." — Hannah Brown
"Sometimes good things fall apart so better things can come together."
"Live for what today has to offer, not for what yesterday has taken away."
"Accept what is, let go of what was, and have faith in what will be."
"Don't be afraid to start over. It’s a brand new opportunity to rebuild what you truly want."
"Inhale the future, exhale the past."
"Don’t cry because it’s over, smile because it happened."
Seven hundred eighteen thousand nine hundred twenty seven
700000+10000+8000+900+20+7
Answer:
school building, so the fourth side does not need Fencing. As shown below, one of the sides has length J.‘ (in meters}. Side along school building E (a) Find a function that gives the area A (I) of the playground {in square meters) in
terms or'x. 2 24(15): 320; - 2.x (b) What side length I gives the maximum area that the playground can have? Side length x : [1] meters (c) What is the maximum area that the playground can have? Maximum area: I: square meters
Step-by-step explanation:
Answer:
AQ1: Divide what she owed by 4
AQ2: -18
