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3 years ago

Y=-x-5 2x+y=5 substitution method

Mathematics

1 answer:

Mumz [18]3 years ago

5 0

Answer:

x = 10

y = -15

Step-by-step explanation:

putting value of y in equation 2

2x+(-x-5)=5

2x-x-5=5

x-5=5

x=5+5

x= 10

putting value of x in equation 1

y=-10-5

y= - 15

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If h(x) = 5 x and k(x)=1/x, which expression is equivalent to (koh)(x)?

Lyrx [107]

May be there is an operator missing in the first function, h(x). I will solve this in two ways, 1) as if the h(x) = 5x and 2) as if h(x) = 5 + x

1) If h(x) = 5x and k(x) = 1/x

Then (k o h) (x) = k ( h(x) ) = k(5x) = 1/(5x)

2) If h(x) = 5 + x and k (x) = 1/x

Then (k o h)(x) =k ( h(x) ) = k (5+x) = 1 / [5 + x]

4 0

2 years ago

Read 2 more answers

Calculate the length b to two decimal places.

Andrej [43]

Answer:

B. 21.64

Step-by-step explanation:

We have been given a triangle and we are asked to find the length of AC (b).

We will use law of cosines to find the length of side AC.

$c^{2}=a^{2}+b^{2}-2ab \text{ cos }\theta$

Upon substituting our given values in the formula we will get,

$(AC)^{2}=15^{2}+12^{2}-2\times 15\times 12 \text{ cos}(106)$

$(AC)^{2}=225+144-360\text{ cos}(106)$

$(AC)^{2}=369-360(-0.275637355817)$

$(AC)^{2}=369+99.22944809412$

$(AC)^{2}=468.22944809412$

Upon taking square root of both sides of our equation we will be get,

$AC=\sqrt{468.22944809412}$

$AC=21.6386101238993629\approx 21.64$

Therefore, the length of b is 21.64 and option B is the correct choice.

6 0

2 years ago

Please help this is for rotc it's due at 6

Gnom [1K]

Answer:

UK, Egypt, India, the Philippines, Colombia,

Step-by-step explanation:

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2 years ago

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Natasha2012 [34]

As we know that the standard equation of circle is ${\bf{(x-h)^{2}+(y-k)^{2}=r^{2}}}$ , where r is the radius of circle and centre at (h,k) 

Now , as the circle passes through (2,9) so it must satisfy the above equation after putting the values of h and k respectively

${:\implies \quad \sf \{2-(-1)\}^{2}+(9-5)^{2}=r^{2}}$