Answer:
x=37°
Step-by-step explanation:
2x°=74° (vertically opposite angles)
2x°/2=74°/2
x=37°
Answer:
JML=142 degrees
Step-by-step explanation:
This shape is a rhombus, as all 4 sides are equal, but the angle measures are not. One of the properties of a rhombus is that opposite angles are congruent, and adjacent angles are supplementary. Only the second one is important. Since angles KLM and angle JML are supplementary, the equation KLM+JML=180 can be used. KLM is then substituted by the given angle measure, 38 degrees, to get an equation such as JML+38=180. Now, to solve for JML, 38 must be subtracted from both sides of the equation, which leaves teh answer of JML=142.
First you have to divide 165 by 3, which is 55. and then 55 multiplied by 8 is 440. so in 8 hours, they could travel 440 miles.
In the balanced reaction
2 Fe + O₂ → 2 FeO
2 moles of iron (Fe) react with 1 mole of molecular oxygen (O₂) to produce 2 moles of iron oxide (FeO). The ratio of Fe to FeO is 1-to-1, so if one starts with 42.4 mol of Fe, one will end up with the same amount of FeO, 42.4 mol.
Look up the molar mass of Fe and O:
• Fe = 55.845 g/mol
• O = 15.999 g/mol
Then the molar mass of FeO is approximately 71.835 g/mol, and so the mass of 42.4 mol of FeO is
(42.4 mol) × (71.835 g/mol) ≈ 3050 g
I've attached the complete question.
Answer:
Only participant 1 is not cheating while the rest are cheating.
Because only participant 1 has a z-score that falls within the 95% confidence interval.
Step-by-step explanation:
We are given;
Mean; μ = 3.3
Standard deviation; s = 1
Participant 1: X = 4
Participant 2: X = 6
Participant 3: X = 7
Participant 4: X = 0
Z - score for participant 1:
z = (x - μ)/s
z = (4 - 3.3)/1
z = 0.7
Z-score for participant 2;
z = (6 - 3.3)/1
z = 2.7
Z-score for participant 3;
z = (7 - 3.3)/1
z = 3.7
Z-score for participant 4;
z = (0 - 3.3)/1
z = -3.3
Now from tables, the z-score value for confidence interval of 95% is between -1.96 and 1.96
Now, from all the participants z-score only participant 1 has a z-score that falls within the 95% confidence interval.
Thus, only participant 1 is not cheating while the rest are cheating.
