Answer:
c. Measuring the differences in blood pressure before, during, and after a procedure.
Step-by-step explanation:
Quantitative research use instruments to measure the variables we are studying. You could measure the variable by using any instrument, in this case the blood preasure during a procedure could be measured with an instrument called sphygmomanometer. Other options couldn't be measured with any instrument.
Answer:
a) 
b) 
c) 
Step-by-step explanation:
a) The slope / gradient is the coefficient of
, so for a) it will be
.
C is the y-intercept, so the full equation will be
.
b) Again, since the slope is 6, we know the coefficient of
will be 6.
Now, we have a point on the line and so far, we know the equation is
. The coordinates of the point are (2,-6). So now we substitute the y and x values into the equation in order to find C.




c) To find the gradient we must use the formula
.
rise = change in y value
run = change in x value
so, the gradient 
Now the equation is 
Again, to find C we substitute any of the coordinates into the equation. I will use (-1,3).



so c) is 
Answer:
-
+ 12
Step-by-step explanation:
h(n) = -4n + 4 (h o g) (n)
g(n) =
- 2
-4(
- 2) + 4
-
+ 8 + 4
-
+ 12
The answer is the product of their slope is -1.
First, let's break this down. Perpendicular lines are line with opposite reciprocal slopes. Opposite meaning the inverse sign and reciprocal meaning flipped.
For instance,
If a line had the slope of 5, its inverse would have a slope of -1/5.
Now, if we multiply these numbers together,
5 * -1/5 = -1
The 5's cancel out.
This works for any two perpendicular lines