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2 years ago

List 21.3 ib 2064 g 16.7 kg 452 oz from least to greatst

Mathematics

1 answer:

lapo4ka [179]2 years ago

3 0

Answer:

2064 g, 21.3 lb, 452 oz, 16.7 kg

Step-by-step explanation:

Let's change all units to grams to be able to compare the amounts.

21.3 lb * 454 g / lb = 9,670.2 g

2064 g = 2064 g

16.7 kg * 1000 g / kg = 16,700 g

452 oz * 1 lb / 16 oz * 454 g / lb = 12,825.5 g

From least to greatest:

2064 g, 21.3 lb, 452 oz, 16.7 kg

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Negative one-sixth of a number is less than -9. write an inequality.

sladkih [1.3K]

Answer:

-1/6 n < -9

Step-by-step explanation:

Negative one-sixth of a number

-1/6 n

is less than -9

-1/6 n < -9

3 0

2 years ago

2x+y=-9 -3x+11=y whathe is the answer

insens350 [35]

[ 2x + y = -9 ] x -3
[- 3x +11= y ] x 2

-6x -3y = 27
-6x + 22 = 2y

-6x +27 = 3y
-6x +22 = 2y

5 = y

-6x -3x5 = 27
-6x -15 = 27
-6x = 42
-x = 42/6
-x = 7
x = -7

answer

x = -7
y = 5

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3 years ago

The wettest April for Albuquerque, NM, was recorded in 1905. The amount was 1.2in more than the amount recorded for the second w

SCORPION-xisa [38]

The 1905 was 3.0 inches while 2004 was 4.2 inches since they are 1.2 apart and they add up to 7.2

4 0

3 years ago

you only have to answer one, dont answer one thats been answered. also english please im a baby who wont learn new languages.

shepuryov [24]

Answer:

1. x=11

Step-by-step explanation:

2x+5=27

Subtract 5 from both sides

2x=22

Divide 2 from both sides

x=11

4 0

2 years ago

Read 2 more answers

A builder wants to build the bridge whose cross section is shown in the diagram. Two companies offer simple bids on building the

leva [86]

The length of the bridge is the distance from the beginning to the end.

The distance b between each beam is 9ft.

Let:

$I \to$ I-Beam

$d_I \to$ distance between I beam and the bridge

$b \to$ distance between each I beam

Given that:

$I = \frac 34 ft\\$

$d_I = 3 ft$

$Length = 55ft\ 6in$ --- length of the bridge

From the diagram (see attachment), there are: 6 I-beams.

So, the length of the 6 I-beams is:

$L_1 = 6 \times I$

$L_1 = 6 \times \frac 34$

$L_1 = \frac {18}4$

$L_1 = 4.5ft$

There are 2 I-beams beside the bridge

So, the distance between the 2 I-beams and the bridge is:

$d_1 =2 \times d_I$

$d_1 =2 \times 3ft$

$d_1 =6ft$

There are 5 spaces between the I-beams

So, the length of the total spaces is:

$L_2 = 5 \times b$

$L_2 = 5b$

The total length is:

$Length = L_1 + d_1 + L_2$

So, we have:

$4.5ft + 6ft + 5b = 55ft\ 6in$

Collect like terms

$5b = 55ft\ 6in - 4.5ft - 6ft$

$5b = 44.5ft\ 6in$

Convert inches to feet

$5b = 44.5ft\ + \frac{6}{12}ft$

$5b = 44.5ft\ + 0.5ft$

$5b = 45ft$

Divide both sides by 5

$b = 9ft$

Hence, the distance (b) between each beam is 9ft.