Answer:
x = ![\frac{17}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B17%7D%7B3%7D)
Step-by-step explanation:
![\frac{10}{x-4}=6\\\\](https://tex.z-dn.net/?f=%5Cfrac%7B10%7D%7Bx-4%7D%3D6%5C%5C%5C%5C)
10 = 6*(x -4)
10 = 6*x - 6*4
10 = 6x - 24
Add 24 to both sides
10 + 24 = 6x - 24 + 24
34 = 6x
6x = 34
Divide both sides by 6
6x/6 = 34/6
x = ![\frac{17}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B17%7D%7B3%7D)
Answer:
a and e
Step-by-step explanation:
12:48 12/4 = 3 48/4 = 12 3:12
Use same method for the rest
Answer: 13
Step-by-step explanation:
8-10= 2 - 9 = 11 - 2 = 13 soo that how you got the answer 13 .
Value? Unclear what you mean. i think you're asking to multiply x(5x)(3x+12). That won't give you a value, but rather an expression.
x*5x comes to 5x^2.
Then 5x^2(3x+12) comes to 15x^3 + 60x^2 (answer)
Answer: Choice A
y=2x+3; y=-1/3x+3
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Explanation:
The left portion of the blue curve is y = 2x+3 but it is only graphed when x < 0 (we could argue that
but I'll set that aside for the other portion).
The right portion is the line y = -1/3x + 3 and it's only graphed when ![x \ge 0](https://tex.z-dn.net/?f=x%20%5Cge%200)
So we could have this piecewise function
![f(x) = \begin{cases}2x+3 \ \text{ if } x < 0\\-\frac{1}{3}x+3 \ \text{ if } x \ge 0\\\end{cases}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cbegin%7Bcases%7D2x%2B3%20%5C%20%5Ctext%7B%20if%20%7D%20x%20%3C%200%5C%5C-%5Cfrac%7B1%7D%7B3%7Dx%2B3%20%5C%20%5Ctext%7B%20if%20%7D%20x%20%5Cge%200%5C%5C%5Cend%7Bcases%7D)
Or we could easily swap the "or equal to" portion to move to the first part instead like this
![f(x) = \begin{cases}2x+3 \ \text{ if } x \le 0\\-\frac{1}{3}x+3 \ \text{ if } x > 0\\\end{cases}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cbegin%7Bcases%7D2x%2B3%20%5C%20%5Ctext%7B%20if%20%7D%20x%20%5Cle%200%5C%5C-%5Cfrac%7B1%7D%7B3%7Dx%2B3%20%5C%20%5Ctext%7B%20if%20%7D%20x%20%3E%200%5C%5C%5Cend%7Bcases%7D)
Either way, we're involving the equations mentioned in choice A