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3 years ago

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a party rental company has chairs and tables for rent. the total cost to rent 5 chairs and 3 tables is 34. the total cost to ren

t 7 chairs and 9 tables is 80. what is the cost to rent each chair and each table?

1 answer:

Art [367]3 years ago

3 0

Answer:

Cost to rent each chair: 1.75

Cost to rent each table: 10.75

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Plz help i need answer ASAP

Reika [66]

Answer:

y = 2x + 2

Step-by-step explanation:

<h3><u>Reading</u><u> </u><u>the</u><u> </u><u>graph</u><u>!</u></h3>

The line shown in the figure cuts the y-axis 2 units above the origin, I.e.,

the point (0, 2)

The line also meets the x-axis two units before the origin, I.e.,

the point (-1, 0)

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3><u>Intercepts</u><u>:</u></h3>

<em>When a line </em><em>meets</em><em> </em><em>both</em><em> </em><em>the</em><em> </em><em>axes</em><em> </em><em>(</em><em>x-axis</em><em> </em><em>and</em><em> </em><em>y-axis</em><em>)</em><em>,</em><em> </em><em>it</em><em> </em><em>forms</em><em> </em>intercepts.

There are two types of intercepts:

x-intercept (<em>when</em><em> </em><em>the</em><em> </em><em>line</em><em> </em><em>meets</em><em> </em><em>the</em><em> </em><em>x-axis</em><em>)</em>
y-intercept (<em>when</em><em> </em><em>the</em><em> </em><em>line</em><em> </em><em>meets</em><em> </em><em>the</em><em> </em><em>y-axis</em><em>)</em>

Each of their length is equal to their distance from the Origin(0, 0)

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3><u>Equation of a line (intercept form):</u></h3>

If the x-intercept is denoted by "a" and y-intercept by "b", the equation if such a line is given by:

$\boxed{ \mathsf{ \frac{x}{a} + \frac{y}{b} = 1 }}$

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3><u>Equation</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>line</u><u> </u><u>in</u><u> </u><u>question</u><u>:</u></h3>

x-intercept (a) = -1
y-intercept (b) = 2

$\implies \mathsf{ \frac{x}{( - 1)} + \frac{y}{2} = 1 }$

<em>The</em><em> </em><em>sign</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>denominator</em><em> </em><em>is</em><em> </em><em>taken</em><em> </em><em>by</em><em> </em><em>the</em><em> </em><em>numerator</em><em>:</em>

$\implies \mathsf{ - \frac{x}{1} + \frac{y}{2} = 1 }$

<em>Taking</em><em> </em><em>LCM</em><em>:</em>

$\implies \mathsf{ \frac{ - 2x + y}{ 2} = 1 }$

<em>Cross</em><em> </em><em>multiplying</em><em>:</em>

$\implies \mathsf{ - 2x + y = 2 }$

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<em>Isolating</em><em> </em><em>y</em><em>:</em>

<em> $\implies \mathsf{ \underline{ y = 2 + 2x }}$ </em>

That's the equation of the given line!

6 0

3 years ago

Finding an angle measure given extended triangles

rodikova [14]

Answer:

x = 180 - 32 - 43 - 72 = 33°

4 0

3 years ago

Find the LCD of the rational expression<br> Problems 3,4,5<br> Please help!!!

horrorfan [7]

The LCD of the rational expressions are 30x^5, (3x - 1)(x + 6) and (x + 3)(x + 5)^2

<h3>How to determine the LCD of the rational expressions?</h3>

<u>Expression 1</u>

The rational expressions are given as:

3/10x^2 and x + 7/15x^5

Write out the denominators

10x^2 and /15x^5

Expand each of the denominator.

10x^2 = 2 * 5 * x * x

15x^5 = 3 * 5 * x* x * x * x * x

Multiply all common factors without repetition

So, the LCD of the denominators are

LCD = 2 * 3 * 5 * x* x * x * x * x

Evaluate

LCD = 30x^5

<u>Expression 2</u>

The rational expressions are given as:

9/3x - 1 and 2x/x + 6

Write out the denominators

3x - 1 and x + 6

Expand each of the denominator.

10x^2 = 3x - 1

15x^5 = x + 6

Multiply all common factors without repetition

So, the LCD of the denominators are

LCD = (3x - 1)(x + 6)

<u>Expression 3</u>

The rational expressions are given as:

8x/(x + 5)^2 and 4x + 1/x^2 + 8x + 15

Write out the denominators

(x + 5)^2 and x^2 + 8x + 15

Expand each of the denominator.

(x + 5)^2 = (x + 5) * (x + 5)

x^2 + 8x + 15 = (x + 3) * (x + 5)

Multiply all common factors without repetition

So, the LCD of the denominators are

LCD = (x + 3) * (x + 5) * (x + 5)

LCD = (x + 3)(x + 5)^2

Hence, the LCD of the rational expressions are 30x^5, (3x - 1)(x + 6) and (x + 3)(x + 5)^2

Read more about LCD at:

brainly.com/question/1025735

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