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Ainat [17]
3 years ago
15

Plz help i need answer ASAP

Mathematics
1 answer:
Reika [66]3 years ago
6 0

Answer:

y = 2x + 2

Step-by-step explanation:

<h3><u>Reading</u><u> </u><u>the</u><u> </u><u>graph</u><u>!</u></h3>
  • The line shown in the figure cuts the y-axis 2 units above the origin, I.e.,

the point (0, 2)

  • The line also meets the x-axis two units before the origin, I.e.,

the point (-1, 0)

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3><u>Intercepts</u><u>:</u></h3>

<em>When a line </em><em>meets</em><em> </em><em>both</em><em> </em><em>the</em><em> </em><em>axes</em><em> </em><em>(</em><em>x-axis</em><em> </em><em>and</em><em> </em><em>y-axis</em><em>)</em><em>,</em><em> </em><em>it</em><em> </em><em>forms</em><em> </em>intercepts.

There are two types of intercepts:

  • x-intercept (<em>when</em><em> </em><em>the</em><em> </em><em>line</em><em> </em><em>meets</em><em> </em><em>the</em><em> </em><em>x-axis</em><em>)</em>
  • y-intercept (<em>when</em><em> </em><em>the</em><em> </em><em>line</em><em> </em><em>meets</em><em> </em><em>the</em><em> </em><em>y-axis</em><em>)</em>

Each of their length is equal to their distance from the Origin(0, 0)

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3><u>Equation of a line (intercept form):</u></h3>

If the x-intercept is denoted by "a" and y-intercept by "b", the equation if such a line is given by:

\boxed{ \mathsf{ \frac{x}{a}  +  \frac{y}{b} = 1 }}

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3><u>Equation</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>line</u><u> </u><u>in</u><u> </u><u>question</u><u>:</u></h3>
  • x-intercept (a) = -1
  • y-intercept (b) = 2

\implies \mathsf{ \frac{x}{( - 1)} +  \frac{y}{2}  = 1 }

<em>The</em><em> </em><em>sign</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>denominator</em><em> </em><em>is</em><em> </em><em>taken</em><em> </em><em>by</em><em> </em><em>the</em><em> </em><em>numerator</em><em>:</em>

\implies \mathsf{  - \frac{x}{1} +  \frac{y}{2}  = 1 }

<em>Taking</em><em> </em><em>LCM</em><em>:</em>

\implies \mathsf{  \frac{ - 2x + y}{ 2}   = 1 }

<em>Cross</em><em> </em><em>multiplying</em><em>:</em>

\implies \mathsf{  -  2x + y = 2 }

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<em>Isolating</em><em> </em><em>y</em><em>:</em>

<em>\implies \mathsf{  \underline{  y = 2 + 2x }}</em>

That's the equation of the given line!

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<h3>Answer:   -7/2</h3>

=========================================================

Explanation:

Let's expand out (2 - 7i)(a + bi) using the FOIL rule

(2 - 7i)(a + bi) = 2a + 2bi - 7ai - 7bi^2

(2 - 7i)(a + bi) = 2a + 2bi - 7ai - 7b(-1)

(2 - 7i)(a + bi) = 2a + 2bi - 7ai + 7b

(2 - 7i)(a + bi) = (2a+7b) + (2bi-7ai)

(2 - 7i)(a + bi) = (2a+7b) + (2b-7a)i

We're told the result is purely imaginary. What this means is that the real part (2a+7b) is zero, while the imaginary part (2b-7a) is nonzero. If both are zero, then we have 0+0i = 0 which is purely real.

For example, the complex numbers 0-7i and 0+2i are purely imaginary.

Let's use the fact that 2a+7b must be zero to do the following steps:

2a+7b = 0

2a = -7b

a = -7b/2

a/b = -7/2 which is the final answer

We must check to see if 2b-7a is nonzero

2b - 7a = 2b - 7(-7b/2)

2b - 7a = 2b + 24.5b

2b - 7a = 26.5b

The result is nonzero if and only if b is nonzero. Luckily we're told b is nonzero at the top of the problem. So we don't have any worries that (2b-7a) is zero.

Therefore, (2a+7b) + (2b-7a)i will be purely imaginary with a/b = -7/2

------------------

A concrete example:

Let a = -14 and b = 4

a/b = -14/4 = -7/2

(2-7i)(a+bi) = (2-7i)(-14+4i) = 0 + 106i which is purely imaginary.

I'll let you do the steps in expanding that out using the FOIL rule.

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Step-by-step explanation:

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