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Ainat [17]
2 years ago
15

Plz help i need answer ASAP

Mathematics
1 answer:
Reika [66]2 years ago
6 0

Answer:

y = 2x + 2

Step-by-step explanation:

<h3><u>Reading</u><u> </u><u>the</u><u> </u><u>graph</u><u>!</u></h3>
  • The line shown in the figure cuts the y-axis 2 units above the origin, I.e.,

the point (0, 2)

  • The line also meets the x-axis two units before the origin, I.e.,

the point (-1, 0)

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3><u>Intercepts</u><u>:</u></h3>

<em>When a line </em><em>meets</em><em> </em><em>both</em><em> </em><em>the</em><em> </em><em>axes</em><em> </em><em>(</em><em>x-axis</em><em> </em><em>and</em><em> </em><em>y-axis</em><em>)</em><em>,</em><em> </em><em>it</em><em> </em><em>forms</em><em> </em>intercepts.

There are two types of intercepts:

  • x-intercept (<em>when</em><em> </em><em>the</em><em> </em><em>line</em><em> </em><em>meets</em><em> </em><em>the</em><em> </em><em>x-axis</em><em>)</em>
  • y-intercept (<em>when</em><em> </em><em>the</em><em> </em><em>line</em><em> </em><em>meets</em><em> </em><em>the</em><em> </em><em>y-axis</em><em>)</em>

Each of their length is equal to their distance from the Origin(0, 0)

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3><u>Equation of a line (intercept form):</u></h3>

If the x-intercept is denoted by "a" and y-intercept by "b", the equation if such a line is given by:

\boxed{ \mathsf{ \frac{x}{a}  +  \frac{y}{b} = 1 }}

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3><u>Equation</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>line</u><u> </u><u>in</u><u> </u><u>question</u><u>:</u></h3>
  • x-intercept (a) = -1
  • y-intercept (b) = 2

\implies \mathsf{ \frac{x}{( - 1)} +  \frac{y}{2}  = 1 }

<em>The</em><em> </em><em>sign</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>denominator</em><em> </em><em>is</em><em> </em><em>taken</em><em> </em><em>by</em><em> </em><em>the</em><em> </em><em>numerator</em><em>:</em>

\implies \mathsf{  - \frac{x}{1} +  \frac{y}{2}  = 1 }

<em>Taking</em><em> </em><em>LCM</em><em>:</em>

\implies \mathsf{  \frac{ - 2x + y}{ 2}   = 1 }

<em>Cross</em><em> </em><em>multiplying</em><em>:</em>

\implies \mathsf{  -  2x + y = 2 }

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<em>Isolating</em><em> </em><em>y</em><em>:</em>

<em>\implies \mathsf{  \underline{  y = 2 + 2x }}</em>

That's the equation of the given line!

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Suppose that Adam rolls a fair six-sided die and a fair four-sided die simultaneously. Let AAA be the event that the six-sided d
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The question is incomplete. Here is the complete question.

Suppose that Adam rolls a fair six-sided die and a fair four-sided die simultaneously. Let A be the event that the six-sided die is an even number and B be the event that the four-sided die is an odd number. Using the sample space of possible outcomes below, answer each of the following questions.

What is P(A), the probabillity that the six-sided die is an even number?

What is P(B), the probability of the four-sided die is an odd number?

What is P(A and B), the probability that the six-sided die is an even number  <em>and</em> the four-sided die is an odd number?

Are events A and B independent?

a) Yes, events A and B are independent events.

b) No, events A and B are not independent events.

Answer: P(A) = 1/2

P(B) = 1/2

P(A and B) = 1/4

a) Yes, events A and B are independent events.

Step-by-step explanation: The event A is related to a six-sided die, so total possibilities is 6.

For a six-sided die to show a even number, there are 3 possibilities: (2,4,6)

so, P(A) = 3/6 = 1/2

The event B is for a 4-sided die, i.e. total possibilities is 4.

To show an odd number, there are 2 possibilities: (1,3).

Then, P(B) = 2/4 = 1/2

Now, the probability of occuring A and B is:

P(A and B) = P(A).P(B)

P(A and B) = 1/2*1/2

P(A and B) = 1/4

The events are <u>independent</u> events because the probability of A happening does not influence the occuring of event B.

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