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Advocard [28]
3 years ago
12

Help!!!

Mathematics
1 answer:
Crank3 years ago
7 0

Using a system of equations, it is found that:

  • Each pound of strawberry cost $3.
  • Each pound of grape cost $1.25.
  • Each pound of melon costs $4.75.

--------------------

For our system, we have that:

  • x is the cost of a pound of strawberry.
  • y is the cost of a pound of grape.
  • z is the cost of a pound of melon.

Three pounds of  strawberries, five pounds of grapes, and one pound of melon at a cost of $20.

This means that:

3x + 5y + z = 20

z = 20 - 3x - 5y

Three pounds of strawberries, two pounds of grapes, and two pounds of melon at a cost of $21.

This means that:

3x + 2y + 2z = 21

3x + 2y + 2(20 - 3x - 5y) = 21

3x + 2y + 40 - 6x - 10y = 21

3x + 8y = 19

Four pounds of strawberries, three pounds of grapes, and three pounds of melon  at a cost of $30.

This means that:

4x + 3y + 3z = 30

4x + 3y + 3(20 - 3x - 5y) = 30

4x + 3y + 60 - 9x - 15y = 30

5x + 12y = 30

For x and y, the system is:

3x + 8y = 19

5x + 12y = 30

Multiplying by 5 and -3, we get:

15x + 40y = 95

-15x - 36y = -90

Then, adding them:

4y = 5

y = \frac{5}{4}

y = 1.25

Each pound of grape cost $1.25.

Solving for x:

5x + 12y = 30

5x + 12(1.25) = 30

5x = 15

x = \frac{15}{5}

x = 3

Each pound of strawberry cost $3.

Finally, for z:

z = 20 - 3x - 5y

z = 20 - 3(3) - 5(1.25)

z = 4.75

Each pound of melon costs $4.75.

A similar problem is given at brainly.com/question/17096268

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