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Harlamova29_29 [7]
2 years ago
6

There are two jars of sweets.

Mathematics
1 answer:
qwelly [4]2 years ago
4 0
First, we model two equations that satisfy the problem. Let x be the number of sweets in the first jar, and y the number of sweets in the second jar.
First equation:
(x-20)/1 = (y+20)/2 
or
(x-20)/(y+20) = 1/2

Second equation:
[(x-20)+60]/3 = [(y+20)-60]/1
or 
(x+40) = 3(y-40)

Expressing the first equation in terms of y, we have:
y = 2x - 60

Plugging it in to the second equation:
(x+40) = 3[(2x-60) - 40]
5x = 340
x = 68

y = 2(68)-60 = 76

The first jar originally had 68 sweets and the second jar originally had 76 sweets.
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Answer:

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Step-by-step explanation:

We are provided with function, f ( x ) = 3 x^{2} + kx − 13

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Here,

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or 20 = 4k

or 4k = 20

k = \frac{20}{4}

<h2>k = 5</h2>

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