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coldgirl [10]
3 years ago
5

Scale the numerator and the denominator down by a factor of 4 (divide) to write a fraction equivalent to 8/56. (i really need he

lp with this)
8/56 = ??
Mathematics
1 answer:
harina [27]3 years ago
3 0

Answer:

2/14

Step-by-step explanation:

when you scale the numerator and denominator down by 4, you just divide both of them by 4. So since 8 divided by 4 is 2 and 56 divided by 4 is 14, the answer is 2/14

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Round 2 5/6 to the nearest half
Mekhanik [1.2K]
(2 5/6):2 = (2 5/6) * 1/2 = (12/6 + 5/6)*1/2 = 17/6*1/2 = 17/12 = 1 5/12
7 0
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If the sum of a term of an ap is 2n square + 5n then find the 4th term​
zlopas [31]

Answer:

19

Step-by-step explanation

Let the sum of n terms of A.P. = Sn

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The distance d in miles that can be covered by a rabbit in X hours is given in the equation y = 30 x The distance covered by a b
AveGali [126]

Answer:

Rabbit is faster than bear.

Step-by-step explanation:

Speed of rabbit or bear is determined by their rate of change of their distances with time.

The distance covered by rabbit in x hours is given as:

y=30x

The above equation is of the form y=mx, where, m is the rate of change of y with x.

Therefore, the rate of change of rabbit's distance with time is 30 mi/h.

Now, from the graph, the slope is given as the rise over run.

Rise is 50 miles and run is 2 miles.

So, rate of change of bear's distance with time is, m_b=\frac{50}{2}=25\ mi/h

Now, 30 is greater than 25. So, rabbit is faster than bear.

6 0
3 years ago
PLEASE HELP!!!!!!!!!!
Montano1993 [528]
X is equal 25 degrees. Line ac goes though the parallel lines. So bcd is x. Cdb is 180-50 equals 130. All angles add to 180. 180-130 equals 2X. So x equals 25.
5 0
2 years ago
In the circle below, suppose m FEH=272º and m EFG=116º. Find the following.​
adoni [48]

Answer:

m∠FEH = 44°

m∠EHG =  64°

Step-by-step explanation:

1) The given information are;

The angle of arc m∠FEH = 272°, the measured angle of ∠EFG = 116°

Given that m∠FEH = 272°, therefore, arc ∠HGF = 360 - 272 = 88°

Therefore, angle subtended by arc ∠HGF at the center = 88°

The angle subtended by arc ∠HGF at the circumference = m∠FEH

∴ m∠FEH = 88°/2 = 44° (Angle subtended at the center = 2×angle subtended at the circumference)

m∠FEH = 44°

2) Similarly, m∠HGF is subtended by arc m FEH, therefore, m∠HGF = (arc m FEH)/2 = 272°/2 = 136°

The sum of angles in a quadrilateral = 360°

Therefore;

m∠FEH + m∠HGF + m∠EFG + m∠EHG = 360° (The sum of angles in a quadrilateral EFGH)

m∠EHG = 360° - (m∠FEH + m∠HGF + m∠EFG) = 360 - (44 + 136 + 116) = 64°

m∠EHG =  64°.

5 0
3 years ago
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