Tan(-212°) = _____. -cot 32° tan 32° cot 32° -tan 32°
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Y=kx+b
line is perpendicular y=1/3x+6⇒ k=-
=-3
so line y=-3x+a
this line that passes through (-9,12)⇔x=-9, y=12, so 12=-3(-9)+a
12=27+a
a=12-27
a=-15
y=-3x-15
P.s.picture<span> to test solutions <span>in the application</span></span>
line is perpendicular y=1/3x+6⇒ k=-
so line y=-3x+a
this line that passes through (-9,12)⇔x=-9, y=12, so 12=-3(-9)+a
12=27+a
a=12-27
a=-15
y=-3x-15
P.s.picture<span> to test solutions <span>in the application</span></span>