It's difficult to make out what the force and displacement vectors are supposed to be, so I'll generalize.
Let <em>θ</em> be the angle between the force vector <em>F</em> and the displacement vector <em>r</em>. The work <em>W</em> done by <em>F</em> in the direction of <em>r</em> is
<em>W</em> = <em>F</em> • <em>r</em> cos(<em>θ</em>)
The cosine of the angle between the vectors can be obtained from the dot product identity,
<em>a</em> • <em>b</em> = ||<em>a</em>|| ||<em>b</em>|| cos(<em>θ</em>) ==> cos(<em>θ</em>) = (<em>a</em> • <em>b</em>) / (||<em>a</em>|| ||<em>b</em>||)
so that
<em>W</em> = (<em>F</em> • <em>r</em>)² / (||<em>F</em>|| ||<em>r</em>||)
For instance, if <em>F</em> = 3<em>i</em> + <em>j</em> + <em>k</em> and <em>r</em> = 7<em>i</em> - 7<em>j</em> - <em>k</em> (which is my closest guess to the given vectors' components), then the work done by <em>F</em> along <em>r</em> is
<em>W</em> = ((3<em>i</em> + <em>j</em> + <em>k</em>) • (7<em>i</em> - 7<em>j</em> - <em>k</em>))² / (√(3² + 1² + 1²) √(7² + (-7)² + (-1)²))
==> <em>W</em> ≈ 5.12 J
(assuming <em>F</em> and <em>r</em> are measured in Newtons (N) and meters (m), respectively).
The answer is 7 because it’s 7
Answer:
Transitive property
Step-by-step explanation:
I'm so sorry if it's wrong I took geo last year online and I still hated proofs. Transitive property is basically when x=y, y=z so x=z. since <4 and <5 are congruent and <1 and <4 are congruent, that would make <1 and <5 congruent because of the transitive property. Good luck with proofs!
Since they are FEWER than 30 total cones, the sum of x small cones and y large one must be LESS THAN 30: x+y <30
He needs AT LEAST a dozen (12), so that means that 12 will work or more than 12:
Answer:
See the first attachment. The numbers indicate the order 1=least, 5=greatest.
Step-by-step explanation:
This is a calculator exercise. Put the numbers in your calculator and have it tell you the result. Don't forget that (ab)/(cd) = ab/c/d if you don't use parentheses.
See the 2nd and 3rd attachments for the values of the expressions.
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You can estimate values as follows (top to bottom):
1. 4·9·10^(8-5) ≈ 36·10^3
2. 7·8·10^(5-2) ≈ 56·10^3
3. (7·9)/(8·4)·10^(5-7+2+3) ≈ 2·10^3
4. (8·10)/(8·6)·10^(4+1-11+8) ≈ 1.7·10^2
5. (2·6)/(3·5)·10^(4+3+2-2) ≈ 0.8·10^7
These are crude estimates, but sufficiently close to put the numbers in order as required.
