In a strand of DNA, each single nucleotide represents a single letter of the DNA code. The following image represents a segment
1 answer:
The immense amount of information stored in DNA is coded with just four base nucleotides. These four nucleotides are paired by twos to form <u>complementary </u>DNA chains.
The makeup of DNA is limited to two <u>pairs </u>of nucleotides bases. One of these pairs is a pyrimidine base whilst the other forms a purine base. The four nucleotides that will make up the entire DNA code are:
- Adenine (A)
- Guanine (G)
- Cytosine (C)
- Thymine (T).
A and G will pair to form the purine base, meanwhile, Cytosine pairs with Thymine to form the <em>pyrimidine base</em>. As per the entire DNA code, A will always pair with G.
Whilst C always pairs with T. This is due to the very nature of the nucleotides themselves and will not change throughout the synthesis or duplication of DNA. Therefore, to complete the complementary strand described in the assignment we must match the letter given with its corresponding base pair, using this rule of DNA.
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The Hardy-Weinberg equation is as follows:
Where:
(convert all % to decimals)
p= homozygous dominant
q= homozygous recessive
pq= heterozygous
While you did not specify whether the 0.2 frequency was for dominant or recessive, we can still figure out the answer.
Using the 1st equation, we can solve for the other dominant/recessive frequency:
1-0.2=0.8
Meaning that:
p= 0.8 & q=0.2
If the heterozygouz frequency is 2pq, then it becomes a simple "plug & chug" sort of approach.
2(0.8)(0.2)= 2(0.16)= 0.32
So, the heterozygous frequency would be:
0.32
Hope this helps!
Where:
(convert all % to decimals)
p= homozygous dominant
q= homozygous recessive
pq= heterozygous
While you did not specify whether the 0.2 frequency was for dominant or recessive, we can still figure out the answer.
Using the 1st equation, we can solve for the other dominant/recessive frequency:
1-0.2=0.8
Meaning that:
p= 0.8 & q=0.2
If the heterozygouz frequency is 2pq, then it becomes a simple "plug & chug" sort of approach.
2(0.8)(0.2)= 2(0.16)= 0.32
So, the heterozygous frequency would be:
0.32
Hope this helps!