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777dan777 [17]
3 years ago
6

Following are the prices of 12 tickets listed on the Ticket Racket ticket broker site for a Taylor Swift concert.

Mathematics
2 answers:
Ludmilka [50]3 years ago
8 0

Let me use Python to find the answers

Program.

\tt import\:statistics \:as\:stats

\tt Prices=[75,120,120,145,150,150,150,175,175,200,225,275]

\tt print(stats.mean(Prices))

\tt print(stats.median(Prices))

\tt print(stats.mode(Prices))

Output:;

  • Mean=163.333
  • Median=150.0
  • Mode=150

Console attached

katrin2010 [14]3 years ago
3 0

Answer:

  • See below

Step-by-step explanation:

<u>Given prices:</u>

  • $75, $120, $120, $145, $150, $150, $150, $175, $175, $200, $225, $275

a) <u>Find the mean:</u>

  • (75 + 2*120 + 145 +  3*150+ 2*175 + 200 + 225 + 275)/12 = $163.33

b) <u>Find the median</u>

  • The both middle numbers are $150, so it is the median

c) <u>Find the mode:</u>

  • The most repeated price is $150 (3 times repeated)

d) <u>Find the range:</u>

  • $275 - $75 = $200

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miss Akunina [59]

Answer:

Step-by-step explanation:

the answer is 151.20

7 0
3 years ago
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4 years ago
Given that the student is a female what is the probability that she consider's herself to be a "Liberal" ? Round your answer to
il63 [147K]

The answer is D.

0.355


https://quizlet.com/171253209/probability-quiz-amdm-flash-cards/

3 0
4 years ago
Read 2 more answers
What is D of the arithmetic sequence for which a5 equals 24 and a9 equals 40
Gnom [1K]

In an arithmetic sequence d represent the common difference.

The formula to find the general term of an arithmetic sequence is,

a_{n} =a_{1} +(n-1)d

Where a_{n}= nth term and

a_{1} = First term.

Given, a_{5} = 24, a_{9} = 40. Therefore,

a_{1} +(5-1)d = 24  , a_{1} +(9-1)d = 40

a_{1} +4d = 24  , a_{1} +8d = 40

Next step is to subtract the above equations so that we can eliminate a1 and get the value of d. Hence,

4d - 8d = 24 - 40

-4d = - 16

\frac{-4d}{-4}= \frac{-16}{-4} Divide each sides by - 16.

d = 4

So, d = 4.

Hope this helps yoi!.

5 0
3 years ago
Let C = {n ∈ Z | n = 6r – 5 for some integer r} and D = {m ∈ Z | m = 3s + 1 for some integer s}.
noname [10]

Its is true that C ⊆ D means Every element of C is present in D

According to he question,

Let C = {n ∈ Z | n = 6r – 5 for some integer r}

D = {m ∈ Z | m = 3s + 1 for some integer s}

We have to prove : C ⊆ D

Proof : Let n ∈ C

Then there exists an integer r such that:

n = 6r - 5

Since -5 = -6 + 1

=> n = 6r - 6 + 1

Using distributive property,

=> n = 3(2r - 2) +1

Since , 2 and r are the integers , their product 2r is also an integer and the difference 2r - 2 is also an integer then

Let s = 2r - 2

Then, m = 3r + 1 with r some integer and thus m ∈ D

Since , every element of C is also an element of D

Hence ,  C ⊆ D proved !

Similarly, you have to prove D ⊆ C

To know more about integers here

brainly.com/question/15276410

#SPJ4

7 0
2 years ago
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