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3 years ago

4 digit number that is not divisoble by 2,3,5 or 10

Mathematics

1 answer:

elena-14-01-66 [18.8K]3 years ago

7 0

Answer:

isiiqywyysyu the first one the first time in a even if it well y eh I just saw your message garako thiya na na hey I k h I just got home from a ko xa ki xaina the morning to get well soon dd ko we

Step-by-step explanation:

eheuieiriieu to be ei ufuirijwjjeuuwuw to jnndhejfjit

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On a piece of paper, use a protractor to construct right triangle ABC with AB=4 in. , m∠A=90° , and m∠B=45°

SVEN [57.7K]

AC=4 in
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6 0

3 years ago

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. Use the process outlined in the lesson to approximate the number 3√10. Use the approximation √10 ≈3162 277 7.

GaryK [48]

Answer:

sequence of five intervals

(1) 3³ < $3^{\sqrt{10} }$ < $3^{4}$

(2) $3^{3.1}$ < $3^{\sqrt{10} }$ < $3^{3.2}$

(3) $3^{3.16}$ < $3^{\sqrt{10} }$ < $3^{3.17}$

(4) $3^{3.162}$ < $3^{\sqrt{10} }$ < $3^{3.163}$

(5) $3^{3.1622}$ < $3^{\sqrt{10} }$ < $3^{3.1623}$

Step-by-step explanation:

as per question given data

√10 ≈ 3.162 277 7

to find out

sequence of five intervals

solution

as we have given that √10 value that is here

√10 ≈ 3.162 277 7 ........................1

when we find $3^{\sqrt{10} }$ ................2

put here √10 value in equation number 2

we get $3^{\sqrt{10} }$ that is 32.27

sequence of five intervals

(1) 3³ < $3^{\sqrt{10} }$ < $3^{4}$

(2) $3^{3.1}$ < $3^{\sqrt{10} }$ < $3^{3.2}$

(3) $3^{3.16}$ < $3^{\sqrt{10} }$ < $3^{3.17}$

(4) $3^{3.162}$ < $3^{\sqrt{10} }$ < $3^{3.163}$

(5) $3^{3.1622}$ < $3^{\sqrt{10} }$ < $3^{3.1623}$

5 0

3 years ago

Here is my house number on Brookview Way. I hope to see you on

Sedbober [7]

Answer:

54318

Step-by-step explanation:

my teacher told me the numbers are 54,3 and 18

3 0

3 years ago

8 < 4(x+1) show your work

kati45 [8]

8 < 4 (x + 1) Use the Distributive Property
8 < 4x + 4 Subtract 4 from both sides
4 < 4x Divide both sides by 4
1 < x

5 0

3 years ago

Find the iqr of 4 5 6 8 9 10 11 12

77julia77 [94]

Answer:

The interquartile range is 5.

Step-by-step explanation:

Ah, a throwback to interquartile range... let me help :)

4,5,6,8,9,10,11,12

First, you need to know how to use the IQR. The interquartile range is basically known as the process of subtracting the upper quartile and the lower quartile of a set of data. The lower quartile should be written as Q1, and the upper quartile would be labeled as Q3. This would make the midpoint (median) data set Q2, and the highest possible point would be labeled Q4. Next, you have to always understand what you are looking at. For example, let's split the set 5,6,7,8,9,10,11,12 into groups. 5 and 6 would be Q1, 7 and 8 would be Q2, 9 and 10 would be Q3, and last but not least, 11 and 12 would be labeled as Q4. Now take Q1 and subtract it from Q3 and that is how you get your IQR.

3 0

3 years ago

Read 2 more answers