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2 years ago

9

For every 9 miles lana jogged. Victor jogged 5 miles. If lana jogged 1 how many miles would Victor have jogged?

1 answer:

mash [69]2 years ago

8 0

Answer: .55555555 miles

Step-by-step explanation: we need to divide 9 by 5 to get the answer

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Help plzzzzzzzzzzzzzzz

Tasya [4]

Answer:

3.843

Step-by-step explanation:

(3x1)= 1

(8x1/10= 0.8

(4x1/100)=0.04

(3x1/1000)=0.003

Then, add together to get 3.843.

5 0

2 years ago

Expand the brackets 5(2x + 3)

zimovet [89]

Answer:

10x+15

Step-by-step explanation:

5 x 2x=10x

5x3=15

5 0

2 years ago

Read 2 more answers

Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro

Ugo [173]

Answer:

$Side\ B = 6.0$

$\alpha = 56.3$

$\theta = 93.7$

Step-by-step explanation:

Given

Let the three sides be represented with A, B, C

Let the angles be represented with $\alpha, \beta, \theta$

[See Attachment for Triangle]

$A = 10cm$

$C = 12cm$

$\beta = 30$

What the question is to calculate the third length (Side B) and the other 2 angles ( $\alpha\ and\ \theta$ )

Solving for Side B;

When two angles of a triangle are known, the third side is calculated as thus;

$B^2 = A^2 + C^2 - 2ABCos\beta$

Substitute: $A = 10$ , $C =12$ ; $\beta = 30$

$B^2 = 10^2 + 12^2 - 2 * 10 * 12 *Cos30$

$B^2 = 100 + 144 - 240*0.86602540378$

$B^2 = 100 + 144 - 207.846096907$

$B^2 = 36.153903093$

Take Square root of both sides

$\sqrt{B^2} = \sqrt{36.153903093}$

$B = \sqrt{36.153903093}$

$B = 6.0128115797$

$B = 6.0$ <em>(Approximated)</em>

Calculating Angle $\alpha$

$A^2 = B^2 + C^2 - 2BCCos\alpha$

Substitute: $A = 10$ , $C =12$ ; $B = 6$

$10^2 = 6^2 + 12^2 - 2 * 6 * 12 *Cos\alpha$

$100 = 36 + 144 - 144 *Cos\alpha$

$100 = 36 + 144 - 144 *Cos\alpha$

$100 = 180 - 144 *Cos\alpha$

Subtract 180 from both sides

$100 - 180 = 180 - 180 - 144 *Cos\alpha$

$-80 = - 144 *Cos\alpha$

Divide both sides by -144

$\frac{-80}{-144} = \frac{- 144 *Cos\alpha}{-144}$

$\frac{-80}{-144} = Cos\alpha$

$0.5555556 = Cos\alpha$

Take arccos of both sides

$Cos^{-1}(0.5555556) = Cos^{-1}(Cos\alpha)$

$Cos^{-1}(0.5555556) = \alpha$

$56.25098078 = \alpha$

$\alpha = 56.3$ <em>(Approximated)</em>

Calculating $\theta$

Sum of angles in a triangle = 180

Hence;

$\alpha + \beta + \theta = 180$

$30 + 56.3 + \theta = 180$

$86.3 + \theta = 180$

Make $\theta$ the subject of formula

$\theta = 180 - 86.3$

$\theta = 93.7$

5 0

2 years ago

Lamont builds a triangular shape fence to hide his pool pump

Monica [59]

I don't understand what you are trying to say

5 0

3 years ago

HELP ME PLEASE! HALF-DONE ANSWERS WILL BE DELETED! 15 POINTS!

Leni [432]

Answer:

G) Yes, because the plots and the linear model both align to produce a similar calculated sum.

H) I need to see the data table again for step 2d.

Step-by-step explanation:

1.) You scatter plot should be off by 6.97, since that was the first difference in your data table set of terms.

Basically subtract all of the GPAs from the Hours in the table.

Ex). Hours - GPA = Difference

or like before,

9.2 - 2.23 = 6.97

Do the rest of the numbers like this then plot the answers. I'd advise you plot your second set of scatter plot points in a different color.

6 0

3 years ago

Read 2 more answers