Question

Find the value of a square + b square when a+b = 8 and ab = 10

Answer 1

As we know,

$\boxed{ \boxed{(a + b) {}^{2} = {a}^{2} + {b}^{2} + 2ab}}$

now, let's plug the given values to find a² + b²

• $(8) {}^{2} = {a}^{2} + {b}^{2} + (2 \times 10)$

• $64 = {a}^{2} + {b}^{2} + 20$

• ${a}^{2} + {b}^{2} = 64 - 20$

• $a {}^{2} + b {}^{2} = 44$