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notka56 [123]
3 years ago
11

Plsss help urgent !

Mathematics
1 answer:
Firdavs [7]3 years ago
6 0
Linear function maybe?
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A health club charges non-members $5 per day to swim and $9 per day for an exercise class. Members pay a yearly fee of $300 plus
Ivahew [28]

The number of days d, he must use the gym to make the membership worthwhile is at least 21 days

Equation

Non members:

Cost of swimming per day = $5

Cost of exercise per day = $9

Total = $5 + $9

= $14

Members:

Yearly fee = $300

Exercise fee per day = $4

Swimming fee = $0

The number of days d, he must use the gym to make the membership worthwhile = $300 ÷ 14

= 21.42857142857142

Approximately,

21 days

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1 year ago
Dan recently bought a new mountain bike for $550. His friend works
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$990
550 x .80 = 440
$550 + $440 = $990
8 0
4 years ago
Does anyone remember how to do this???? i dont need the steps.
Paladinen [302]

Answer:

im sorry I actually forgot

Step-by-step explanation:

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4 0
3 years ago
Two marbles are drawn without replacement from a box with 3 white, 2 green, 2 red, and 1 blue marble. Find the probability that
Likurg_2 [28]
White       3/8
Green      2/8
Red          2/8
Blue          1/8

Blue         1/7
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3 years ago
Use the identity (x^2+y^2)^2=(x^2−y^2)^2+(2xy)^2 to determine the sum of the squares of two numbers if the difference of the squ
marissa [1.9K]

Answer:

Step-by-step explanation:

(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2

Adding and substracting 2x^2y^2

We get

(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2 +2x^2y^2-2x^2y^2

And we know a^2-2ab+b^2=(a-b)^2

So we identify (x^2)^2 as a^2 ,(y^2)^2 as b^2 and -2x^2y^2 as - 2ab. So we can rewrite (x^2+y^2)^2=(x^2 - y^2)^2 + 2x^2y^2 + 2x^2y^2= (x^2 - y^2)^2+4x^2y^2= (x^2 - y^2)^2+2^2x^2y^2

Moreever we know (a·b·c)^2=a^2·b^2·c^2 than means 2^2x^2y^2=(2x·y)^2

And (x^2+y^2)^2=(x^2 - y^2)^2 + (2x·y)^2

5 0
4 years ago
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