It is 9/10 as the others are too small
The equation, when rewritten would be written as:
q = ( c - 54293 ) / 3.59
<h3>How to rewrite the equation in order to make q the subject</h3>
C = 3.59q + 54,293
We have the equation above, what we would have to do now would be to write the equation in such a way that q would be the subject of the formula.
This would be
3.59q = C - 54,293
Next we have to divide through by the value of q
q = 
Read more on subject of formula here: brainly.com/question/21140562
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C. \: x = 2 \: or \: x = 3
Answer:
- r(0) = <0, 100> . . . . . . . .meters
- r'(0) = <7.071, 7.071> . . . . meters per second
Step-by-step explanation:
<u>Initial Position</u>
The problem statement tells us we're measuring position from the ground at the base of the building where the projectile was launched. The initial horizontal position is presumed to be zero. The initial vertical position is said to be 100 meters from the ground, so (in meters) ...
r(0) = <0, 100>
<u>Initial Velocity</u>
The velocity vector resolves into components in the horizontal direction and the vertical direction. For angle α from the horizontal, the horizontal component of velocity is v₁·cos(α), and the vertical component is v₁·sin(α). For v₁ = 10 m/s and α = π/4, the initial velocity vector (in m/s) is ...
r'(0) = <10·cos(π/4), 10·sin(π/4)>
r'(0) ≈ <7.071, 7.071>
