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Vadim26 [7]
2 years ago
14

A balloon is filled to a volume of 700 mL at a pressure of 1.2 atm. The volume is increased 950 ml, what will be the new pressur

e?
Write down all the givens from the problem.

Are all units in the form required to use the generic equation? If not, then show your conversion in the next question.

Show your conversion work

Write the generic equation for this problem. The only variable that is lowercase is for the number of moles – the rest are capitalized. Do not add any spaces between letters and symbols or numbers.

Substitute your numbers into the generic equation. This is where you’re sure you show your math work step-by-step. solve the problem

Enter the numeric portion of your answers here rounded to the nearest hundredth.

Enter the unit of your answer here. Enter it as a symbol not words spelled out if your unit should be capitalized make sure to enter it in that form the answer will be case sensitive
Chemistry
1 answer:
konstantin123 [22]2 years ago
3 0
P1V1 = P2V2

1.2ATM*(.7 L) = V2 * .95L

V2 = 0.884 Liters or 884.21 ml
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Count the total number of atoms in sio2:
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What is the difference between physical and chemical change?
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Read 2 more answers
Si Units Worksheet. Use si units to complete
Keith_Richards [23]

\\ \bull\tt\dashrightarrow 2000m=2km

\\ \bull\tt\dashrightarrow 9000mL=9L

\\ \bull\tt\dashrightarrow 6L=6000mL

\\ \bull\tt\dashrightarrow 6cm=60mm

\\ \bull\tt\dashrightarrow 1000m=1km

\\ \bull\tt\dashrightarrow 50mm=5cm

\\ \bull\tt\dashrightarrow 4L=4000mL

\\ \bull\tt\dashrightarrow 10000g=10kg

\\ \bull\tt\dashrightarrow 10000m=10km

\\ \bull\tt\dashrightarrow 4000g=4kg

\\ \bull\tt\dashrightarrow 9km=9000m

\\ \bull\tt\dashrightarrow 3kg=3000g

\\ \bull\tt\dashrightarrow 90mm=9cm

\\ \bull\tt\dashrightarrow 4km=4000m

\\ \bull\tt\dashrightarrow 2000g=2kg

\\ \bull\tt\dashrightarrow 400cm=4m

\\ \bull\tt\dashrightarrow 3km=3000m

\\ \bull\tt\dashrightarrow 2cm=20mm

\\ \bull\tt\dashrightarrow 9000g=9kg

8 0
2 years ago
4.81*10^24 atoms of lithium
enyata [817]

Answer:

Mass = 55.52 g

Explanation:

Given data:

Number of atoms of Li = 4.81×10²⁴ atom

Number of grams = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

For Li:

4.81×10²⁴ atom × 1 mol / 6.022 × 10²³ atom

8 moles

Mass in gram:

Mass = number of moles × molar mass

Mass = 8 mol × 6.94 g/mol

Mass = 55.52 g

4 0
3 years ago
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