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Vadim26 [7]
2 years ago
14

A balloon is filled to a volume of 700 mL at a pressure of 1.2 atm. The volume is increased 950 ml, what will be the new pressur

e?
Write down all the givens from the problem.

Are all units in the form required to use the generic equation? If not, then show your conversion in the next question.

Show your conversion work

Write the generic equation for this problem. The only variable that is lowercase is for the number of moles – the rest are capitalized. Do not add any spaces between letters and symbols or numbers.

Substitute your numbers into the generic equation. This is where you’re sure you show your math work step-by-step. solve the problem

Enter the numeric portion of your answers here rounded to the nearest hundredth.

Enter the unit of your answer here. Enter it as a symbol not words spelled out if your unit should be capitalized make sure to enter it in that form the answer will be case sensitive
Chemistry
1 answer:
konstantin123 [22]2 years ago
3 0
P1V1 = P2V2

1.2ATM*(.7 L) = V2 * .95L

V2 = 0.884 Liters or 884.21 ml
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Calculate the pOH of a 0.0143 M NaOH solution at 25 ⁰C.
arsen [322]

Answer:

A.) 1.845

Explanation:

You can find the pOH using the following equation:

pOH = -log[OH⁻]

Since NaOH dissociates into 1 Na⁺ and 1 OH⁻, the concentration of both ions is 0.0143 M.

pOH = -log[OH⁻]

pOH = -log[0.0143]

pOH = 1.845

5 0
2 years ago
Fabric is made of ___​
GuDViN [60]

Answer:

Fabric is made of cotton.

Explanation:

Hope that helps :)

6 0
3 years ago
Read 2 more answers
For the following reaction, 4.21 grams of hydrogen gas are allowed to react with 10.6 grams of ethylene (C2H4) . hydrogen(g) + e
sergiy2304 [10]

Answer:a)  11.34 g of ethane (C_2H_6) can be formed

b) C_2H_4 is the limiting reagent

c) 3.44 g of the excess reagent remains after the reaction is complete

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}\times{\text{Molar Mass}}    

1. \text{Moles of} H_2=\frac{4.21}{2}=2.10moles

2. \text{Moles of} C_2H_4=\frac{10.6}{28}=0.378moles

H_2(g)+C_2H_4(g)\rightarrow C_2H_6(g)

According to stoichiometry :

1 mole of C_2H_4 require 1 mole of H_2

Thus 0.378 moles of C_2H_4 will require=\frac{1}{1}\times 0.378=0.378moles  of H_2

Thus C_2H_4 is the limiting reagent as it limits the formation of product and H_2 is the excess reagent.

moles of H_2 left = (2.10-0.378) = 1.72 moles

mass of H_2 left=moles\times {\text {Molar mass}}=1.72moles\times 2g/mol=3.44g

According to stoichiometry :

As 1 mole of C_2H_4 give = 1 mole of C_2H_6

Thus 0.378 moles of C_2H_4 give =\frac{1}{1}\times 0.378=0.378moles  of C_2H_6

Mass of C_2H_6=moles\times {\text {Molar mass}}=0.378moles\times 30g/mol=11.34g

Thus 11.34 g of ethane is formed.

4 0
3 years ago
Which skill involves creating representations of complex objects or processes? A. classifying B. predicting C. making models D.
Murljashka [212]

Answer:

C. making models

Explanation:

Making models facilitates constructing depictions of complex objects or practices that enable students to practice and understand how things work which can not be observed and measured directly. Model making needs abstract thinking about the tools and material used, spatial thinking, and well-organized idea of the project to create complex objects.

8 0
3 years ago
Which sentence describes two atoms that form an ionic bond?
xz_007 [3.2K]

Answer:

The correct answer is "D. The difference in their electronegativities is greater than 1.7"

Explanation:

An ionic bond is produced between metallic and non-metallic atoms, where electrons are completely transferred from one atom to another. During this process, one atom loses electrons and another one gains them, forming ions. Usually, the metal gives up its electrons forming a cation to the nonmetal element, which forms an anion.

So, this type of bond consists of the attraction of atoms with electric charges of different signs, that is, the bond is established when atoms of low electronegative elements (metals) are bonded with atoms of highly electronegative elements (nonmetals).

So you can say that atoms of electronegativity difference equal to or greater than 1.7 participate in this type of bond (with its exceptions).

<u><em>The correct answer is "D. The difference in their electronegativities is greater than 1.7"</em></u>

8 0
3 years ago
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