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shusha [124]
3 years ago
13

How does viscosity of a liquid affect number of collisions?

Chemistry
2 answers:
Pavlova-9 [17]3 years ago
7 0
Viscosity is the ability to flow. Molasses has a low viscosity. If a liquid has a low viscosity there will be less collusion due to less movement 
OlgaM077 [116]3 years ago
6 0
Viscosity is the ability to flow. Molasses has a low viscosity. If a liquid has a low viscosity there will be less collusion due to less movement
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At a certain temperature the rate of this reaction is first order in HI with a rate constant of :0.0632s
Shalnov [3]

Answer : The time taken for the reaction is, 28 s.

Explanation :

Expression for rate law for first order kinetics is given by :

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

where,

k = rate constant  = 0.0632

t = time taken for the process  = ?

[A_o] = initial amount or concentration of the reactant  = 1.28 M

[A] = amount or concentration left time 't' = 1.28\times \frac{17}{100}=0.2176M

Now put all the given values in above equation, we get:

0.0632=\frac{2.303}{t}\log\frac{1.28}{0.2176}

t=28s

Therefore, the time taken for the reaction is, 28 s.

8 0
3 years ago
The equilibrium constant, K, for the following reaction is 2.44×10-2 at 518 K: PCl5(g) PCl3(g) + Cl2(g) An equilibrium mixture o
Volgvan

Answer:

[PCl₅] = 0.5646M

[PCl₃] = 0.1174M

[Cl₂] = 0.1174M

Explanation:

In the reaction:

PCl₅(g) ⇄ PCl₃(g) + Cl₂(g)

K equilibrium is defined as:

<em>K = 2.44x10⁻² = [PCl₃] [Cl₂] / [PCl₅]</em>

The initial moles of each compound when volume is 15.3L are:

PCl₅ = 0.300mol/L×15.3L = 4.59mol

Cl₂ = 8.55x10⁻²mol/L×15.3L = 1.308mol

PCl₃ = 8.55x10⁻²mol/L×15.3L = 1.308mol

At 8.64L, the new concentrations are:

[PCl₅] = 4.59mol / 8.64L = 0.531M

[PCl₃] = 1.308mol / 8.64L = 0.151M

[Cl₂] = 1.308mol / 8.64L = 0.151M

At these conditions, reaction quotient, Q, is:

Q = [0.151M] [0.151M] / [0.531M]

Q = 4.29x10⁻²

As Q > K, <em>the reaction will shift to the left producing more reactant, </em>that means equilibrium concentrations are:

[PCl₅] = 0.531M + X

[PCl₃] = 0.151M - X

[Cl₂] = 0.151M - X

<em>Where X is reaction coordinate.</em>

Replacing in K expression:

2.44x10⁻² = [0.151M - X] [0.151M - X] / [0.531M + X]

1.296x10⁻² + 2.44x10⁻²X = 0.0228 - 0.302X + X²

<em>0 = 9.84x10⁻³ - 0.3264X + X²</em>

Solving for X:

X = 0.293 → False solution. Produce negative concentrations

<em>X = 0.0336M → Right solution.</em>

Replacing:

[PCl₅] = 0.531M + 0.0336

[PCl₃] = 0.151M - 0.0336

[Cl₂] = 0.151M - 0.0336

<h3>[PCl₅] = 0.5646M</h3><h3>[PCl₃] = 0.1174M</h3><h3>[Cl₂] = 0.1174M</h3>
4 0
4 years ago
Will give brilliantiest!! <br> can energy produce more carbon dioxide?
Len [333]

different fuels emit different amounts of carbon dioxide in relation to the energy they produce when burned to analyze

7 0
3 years ago
1.the volume of air in a mountain bicycle tire is constant. the initial pressure and temperature are 3.14 atm and 26 degrees cel
sattari [20]

Answer:

Explanation:

Givens

P1 = 3.14 atm

T1 = 26 + 273 = 299

P2 = 3.96

T2 = ?

Equation

P1 / T1 = P2 / T2

Solution

3.14 / 299 = 3.96 / x                   Cross multiply

3.14 x = 299 * 3.96                     Divide by 3.14

x = 299*3.96 / 3.14

x = 1184.04/3.14

x = 377.08 oK                             Take off 273 to get the degrees Centigrade.

x = 104.08 oC

Part B

If you want the temperature to increase, the relationship is a direct  one. That means as the temperature goes up, the pressure will as well. So for a bicycle, it makes sense that the volume remains constant. That makes the formula above without volume because the volume would cancel out on both sides of the equation.

So as the pressure increases, the particles making up the air begin to respond by the molecules moving faster. Temperature really is the a measurement of how fast molecules are moving. So the momentum is increasing. When the particles hit something, it is with a much greater force and that increases the apparent pressure.

3 0
3 years ago
What does HHPS stand for?​
maw [93]

Answer:

it stands for Hazardous Household Products Symbols.

4 0
4 years ago
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