Ask question

Ask question

All categories

2 years ago

7

A line segment of length k is divided into 3 equal parts what is the distance between midpoints of the first and third segments

1 answer:

anastassius [24]2 years ago

4 0

Line segment of length k is divided into 3 equal parts.

so first segment is 0-k/3 and third segment is 2/3k-k

so mid-pt of 1st = k/6 and 3rd = 5/6k

so the distance in between = 5/6k-k/6 = 4/6k = 2/3k

You might be interested in

Which fraction is equal to 1/5.<br> Can someone please answer this question

NeX [460]

Answer:

2/10

20/100

5/25

Step-by-step explanation:

I hope this helps you

4 0

2 years ago

Read 2 more answers

Chad wants to know which professional baseball player is most popular among the 300 students at his school. Which is the most re

mr_godi [17]

Answer:

It could be to: collect data from a sample of every twentieth student who arrives at school one day

7 0

3 years ago

Find the distance of the point (3,4) from the midpoint of the line joining (8,10) and (4,6)

Elis [28]

Answer:

Distance between point $(3,4)$ and midpoint of line joining $(8,10)$ and $(4,6)$ = $5$ units.

Step-by-step explanation:

Given:

Points:

$A(3,4)\\B(8,10)\\C(4,6)$

To find distance from point A to midpoint of BC.

Midpoint M of BC:

$M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\$

$M=(\frac{8+4}{2},\frac{10+6}{2})\\$ [Plugging in points $B(8,10)\ and\ C(4,6)$ ]

$M=(\frac{12}{2},\frac{16}{2})\\$

$M=(6,8)\\$

Distance between A and M:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\$

$D=\sqrt{(6-3)^2+(8-4)^2} \\$ [Plugging in points $A(3,4)\ and\ M(6,8)$ ]

$D=\sqrt{(3)^2+(4)^2} \\$

$D=\sqrt{9+16} \\$

$D=\sqrt{25} \\$

$D=\pm5$

Since distance is always positive ∴ $D= 5$ units

4 0

3 years ago

When you're writing an essay to evaluate something as "good" or "bad" what is MOST important to include in your

Vera_Pavlovna [14]

Answer:

D

Step-by-step explanation:

You need to explain why you feel they are good or bad.

3 0

2 years ago

2. in a class of 50 students, the number of females is 2 more than 5 times the number of males. How many males and females are t

Ber [7]

Answer:

There are 8 males in the class and 42 females.

Step-by-step explanation:

This question can be solved using a system of equations.

I am going to say that:

x is the number of females.

y is the number of males.

Class of 50 students

This means that $x + y = 50$

The number of females is 2 more than 5 times the number of males.

This means that $x = 5y + 2$

So, finding y, the number of males:

$x + y = 50$

$5y + 2 + y = 50$

$6y = 48$

$y = \frac{48}{6}$

$y = 8$

Females:

$x = 5y + 2 = 5*8 + 2 = 42$

There are 8 males in the class and 42 females.

7 0

2 years ago