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sattari [20]
2 years ago
13

Y= Help me please thanks

Mathematics
1 answer:
MArishka [77]2 years ago
4 0

The value of y will be equal to 4.61.

<h3>What is trigonometry?</h3>

Trigonometry is the branch of mathematics that set up a relationship between the sides and angle of the right-angle triangles.

The value of y will be calculated by using the Pythagorean theorem:-

a² + a² = (9√2)²

a = 9

Applying angle property in the triangle:-

tan26 = \dfrac{MK}{9}

9tan26 = MK

LM = 9 - 9tan26

LM = 9 - 4.38

LM = 4.62

Therefore the value of y will be equal to 4.61.

To know more about Trigonometry follow

brainly.com/question/24349828

#SPJ1

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A

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Remember, a proportion is an equation which sets equal ratios equal to each other.

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3 years ago
When cut into 16 equal slices, each slice is 1/16 of the pizza. Express how much of the pizza 8 of these slices would be in deci
antoniya [11.8K]

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0.5

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Hope this helps

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3 years ago
What type of triangle has side lengths 9, 10, and √130? A. obtuse B. not a triangle C. acute D. right
EastWind [94]

Answer: Option C.

Step-by-step explanation:

The lengths of our triangle are:

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If the triangle is a triangle rectangle, by the Pitagoream's theorem we have:

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in this case H is the larger side, this must be √130.

then:

A and B must be 9 and 10.

9^2 + 10^2 = (√130)^2

81 + 100 = 130

This is false, so this is NOT a triangle rectangle, the hypotenuse is shorter than it should be.

Now, we have some kind of rule:

 if A^2 + B^2 = H^2 then we have one angle of 90° and two smaller ones. (triangle rectangle)

 if A^2 + B^2 > H^2 then all the angles are smaller than 90°, this is an acute triangle.

 if A^2 + B^2 < H^2 then we have one angle larger than 90°, this is an obtuse angle.

(H is always the larger side, A and B are the two shorter ones).

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Romashka [77]

Answer:

\huge{ \boxed{ \sf{ \frac{4}{3} }}}

Step-by-step explanation:

\star{ \sf{ \: Let \: the \: points \: be \: A \: and \: B}}

\star{ \sf{ \: Let \: a(2,-1)  \: be \: (x1 \:, y1) \: and \: b (5,3)  \: be \: (x2 \:, y2)}}

\underline{ \sf{Finding \: the \: slope \: of \: the \: line}}

\boxed{ \sf{Slope =  \frac{y2 - y1}{x2 - x1} }}

\mapsto{ \sf{Slope =  \frac{3 - ( - 1)}{5 - 2} }}

\mapsto{ \sf{Slope =  \frac{3 + 1}{5 - 2}}}

\mapsto{ \sf{Slope =  \frac{4}{3} }}

Hope I helped!

Best regards! :D

~\text{TheAnimeGirl}

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