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Lostsunrise [7]
3 years ago
13

I need help with this. -y^2+x^3-4x^3-6y^3+5-2x^3

Mathematics
2 answers:
balandron [24]3 years ago
7 0

Answer:

-y^2-5x^3-6y^3+5

Step-by-step explanation:

Collect the terms

luda_lava [24]3 years ago
3 0

Answer:

Step-by-step explanation:

How to solve your problem

2

+

3

−

4

3

−

6

3

+

5

−

2

3

y^{2}+x^{3}-4x^{3}-6y^{3}+5-2x^{3}

y2+x3−4x3−6y3+5−2x3

Simplify

1

Combine like terms

2

+

3

−

4

3

−

6

3

+

5

−

2

3

y^{2}+{\color{#c92786}{x^{3}}}{\color{#c92786}{-4x^{3}}}-6y^{3}+5{\color{#c92786}{-2x^{3}}}

y2+x3−4x3−6y3+5−2x3

2

−

5

3

−

6

3

+

5

y^{2}{\color{#c92786}{-5x^{3}}}-6y^{3}+5

y2−5x3−6y3+5

2

Rearrange terms

Solution

−

5

3

−

6

3

+

2

+

5

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6 0
3 years ago
Triangle ABC is isosceles with AB=CB. Circle M is inscribed in Triangle ABC such that it is tangent at points D, E, and F. If th
Ierofanga [76]

Answer:

The answer is "12 inches".

Step-by-step explanation:

Please find the image file of the graph.

We know AE = CF \ and \ EB = FB so because the triangle is isosceles.

EB = 2x, FB = 2x,\ and \ CF = x when AE is called by x.

We know that AE = AD = x since E and D are tangent points to a circle.

They have CD = CF = x since D and F are tangent points only to circle.

Thus, if the perimeter is 32, the following is the result:

\to AE + EB + BF + FC + CD + DA = 32\\\\\to x + 2x + 2x + x + x + x = 32\\\\\to 8x = 32\\\\\to x = 4

Therefore the length of BC = BF + FC = 2x + x = 3x = 12\  inches

8 0
3 years ago
Marty bought 4 new books today. he plans to read 2 of these while on vacation. how many combinations of 2 books from the group o
Grace [21]
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8 0
3 years ago
A secant and a tangent to a circle intersect in a 42-degree angle. The two arcs of the circle intercepted by the secant and the
Amanda [17]

Answer:

The measure of the third arc is 150\°

Step-by-step  explanation:

step 1

we know that

The measurement of the external angle is the semi-difference of the arcs which comprises

in this problem

Let

x----> the greater arc of the circle intercepted by the secant and the tangent

y----> the smaller arc of the circle intercepted by the secant and the tangent

42\°=\frac{1}{2}(x-y)

84\°=(x-y) ----> equation A

\frac{x}{y}=\frac{7}{3}

x=\frac{7}{3}y -----> equation B

Substitute equation B in equation A and solve for y

84\°=(\frac{7}{3}y-y)

84\°=(\frac{4}{3}y)

y=3*84\°/4=63\°

Find the value of x

x=\frac{7}{3}(63\°)=147\°

step 2

Find the measure of the third arc

Let

z------> the measure of the third arc

we know that

x+y+z=360\° -----> complete circle

substitute the values and solve for z

147\°+63\°+z=360\°

z=360\°-(147\°+63\°)=150\°

3 0
3 years ago
Please help I’m really confused and need to learn this
egoroff_w [7]

Answer:

2.

Step-by-step explanation:

For #2, another way to word this question is: For which of the following trig functions is π/2 a solution? Well, go through them one by one. If you plug π/2 into sinθ, you get 1. This means that when x is π/2, y is 1. Try and visualize that. When y is 1, that means you moved off the x-axis; so y = sinθ is NOT one of those functions that cross the x-axis at θ = π/2. Go through the rest of them. For y = cos(π/2), you get 0. At θ = π/2, this function crosses the x-axis. For y = tanθ, your result is undefined, so that doesn't work. Keep going through them. You should see that y = secθ is undefined, y = cscθ returns 1, and y = cotθ returns 0. If you have a calculator that can handle trig functions, just plug π/2 into every one of them and check off the ones that give you zero. Graphically, if the y-value is 0, the function is touching/crossing the x-axis.

Think about what y = secθ really means. It's actually y = 1/(cosθ), right? So what makes a fraction undefined? A fraction is undefined when the denominator is 0 because in mathematics, you can't divide by zero. Calculators give you an error. So the real question here is, when is cosθ = 0? Again, you can use a calculator here, but a unit circle would be more helpful. cosθ = π/2, like we just saw in the previous problem, and it's zero again 180 degrees later at 3π/2. Now read the answer choices.

All multiples of pi? Well, our answer looked like π/2, so you can skip the first two choices and move to the last two. All multiples of π/2? Imagine there's a constant next to π, say Cπ/2 where C is any number. If we put an even number there, 2 will cut that number in half. Imagine C = 4. Then Cπ/2 = 2π. Our two answers were π/2 and 3π/2, so an even multiple won't work for us; we need the odd multiples only. In our answers, π/2 and 3π/2, C = 1 and C = 3. Those are both odd numbers, and that's how you know you only need the "odd multiples of π/2" for question 3.

6 0
3 years ago
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