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2 years ago

I need help with this. -y^2+x^3-4x^3-6y^3+5-2x^3

Mathematics

2 answers:

balandron [24]2 years ago

7 0

Answer:

-y^2-5x^3-6y^3+5

Step-by-step explanation:

Collect the terms

luda_lava [24]2 years ago

3 0

Answer:

Step-by-step explanation:

How to solve your problem

−

y^{2}+x^{3}-4x^{3}-6y^{3}+5-2x^{3}

y2+x3−4x3−6y3+5−2x3

Simplify

Combine like terms

−

y^{2}+{\color{#c92786}{x^{3}}}{\color{#c92786}{-4x^{3}}}-6y^{3}+5{\color{#c92786}{-2x^{3}}}

y2+x3−4x3−6y3+5−2x3

−

y^{2}{\color{#c92786}{-5x^{3}}}-6y^{3}+5

y2−5x3−6y3+5

Rearrange terms

Solution

−

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Express the confidence interval 0.555 less than 0.777 in the form Modifying above p with caret plus or minus Upper E.

Elina [12.6K]

Complete Question

Express the confidence interval 0.555 less than p less than 0.777 in the form Modifying above p with caret plus or minus Upper E.

Answer:

The modified representation is $\r p \pm E = 0.666 \pm 0.111$

Step-by-step explanation:

From the question we are told that

The confidence interval interval is $0.555 < p < 0.777$

Now looking at the values that make up the up confidence interval we see that this is a symmetric confidence interval(This because the interval covers 95% of the area under the normal curve which mean that the probability of a value falling outside the interval is 0.05 which is divided into two , the first half on the left -tail and the second half on the right tail as shown on the figure in the first uploaded image(reference - Yale University ) ) which means

Now since the confidence interval is symmetric , we can obtain the sample proportion as follows

$\r p = \frac{0.555 + 0.777}{2}$

$\r p =0.666$

Generally the margin of error is mathematically represented as

$E = \frac{1}{2} * K$

Where K is the length of the confidence interval which iis mathematically represented as

$K = 0.777 -0.555$

$K = 0.222$

Hence

$ME = \frac{1}{2} * 0.222$

$ME = 0.111$

So the confidence interval can now be represented as

$\r p \pm E = 0.666 \pm 0.111$

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