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NISA [10]
2 years ago
7

Using the quadratic formula to solve 5x = 6x- - 3, what are the values of x?

Mathematics
2 answers:
goldfiish [28.3K]2 years ago
8 0

Answer:

x= -3

Step-by-step explanation:

Solve the rational equation by combining expressions and isolating the variable  x.

kaheart [24]2 years ago
3 0
X = 3

Explanation:
You want to isolate the 3. So you move 6x to the other side of the equal sign which makes it a negative now. Then you add -6x to 5x and you’re left with -x=-3. You never want your leading coefficient and variable to be negative (in this case -1x at the beginning) so you will divide both sides by -1 and get -3/-1 which simplifies to 3
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mrs_skeptik [129]

Answer:

x=9

Step-by-step explanation:

17x - 12 = 114 + 3x

First  Subtract 3x from both sides

14x - 12 = 114

Add 12 to both sides

14x=126

Divide by GCF (14)

x=9

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3 years ago
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Tatiana [17]

Answer:

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2 years ago
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Based on the polynomial remainder theorem, what is the value of the function when x=−6 ?
Vaselesa [24]
ANSWER

f( - 6) =  10


EXPLANATION

The given function is
f(x) =  {x}^{4}  + 8 {x}^{3}  + 10 {x}^{2}  - 7x + 40

According to the remainder theorem,

f( - 6) = R
where R is the remainder when
f(x)

is divided by
x + 6


We therefore substitute the value of x and evaluate to obtain,

f( - 6) =  { (- 6)}^{4}  + 8 {( - 6)}^{3}  + 10 { (- 6)}^{2}  - 7( - 6)+ 40




f( - 6) =  1296 + 8 ( - 216) + 10 (36) - 7( - 6)+ 40




f( - 6) =  1296  - 1728 + 360  + 42+ 40



This will evaluate to,


f( - 6) =  10


Hence the value of the function when
x =  - 6

is
10



According to the remainder theorem,
10
is the remainder when

f(x) =  {x}^{4}  + 8 {x}^{3}  + 10 {x}^{2}  - 7x + 40
is divided by
x + 6
3 0
3 years ago
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