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lara31 [8.8K]
3 years ago
8

What is the solution to the equation?

Mathematics
2 answers:
Bas_tet [7]3 years ago
8 0

Answer:

x=-58

Step-by-step explanation:

emmasim [6.3K]3 years ago
4 0
The answer for the picture would be X=-13/2 or X=-6 1/2
The answer for the other question would be X=-58
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Explain how you know these figures are similar​
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if a snowball rolls down a hill and its surface area increaces at a rate of 18cm^2/min, find the rate at which the radius increa
sp2606 [1]

Answer: dr/dt = 9/(24pi)  cm per minute

9/(24pi) is approximately equal to 0.119366

=============================================

Work Shown:

Given info

dS/dt = 18 cm^2/min is the rate of change of the surface area

r = 6 cm is the radius, from the fact that the diameter is 12 cm

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Use the surface area equation given, apply the derivative, plug in the given values and then isolate dr/dt which represents the rate of change for the radius

S = 4*pi*r^2

dS/dt = 2*4*pi*r*dr/dt

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18 = 8*pi*6*dr/dt

18 = 48*pi*dr/dt

48pi*dr/dt = 18

dr/dt = 18/(48pi)

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dr/dt = 9/(24pi)

The units are cm per minute, which can be written as cm/min.

3 0
3 years ago
Solve x-5y=17 for y?
damaskus [11]

Answer:

Y = 12.

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The Friendly Sausage Factory (FSF) can produce hot dogs at a rate of 5,750 per day. FSF supplies hot dogs to local restaurants a
NARA [144]

Answer:

A) 22812 hotdogs per run

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C) 4 days in a run

Step-by-step explanation:

We are given;

Production rate;p = 5750 per day

Steady Usage rate;u = 270 per day

Setup cost of hotdog;S = $67

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No. of Production days; d = 297 days

A) Let's first find the annual demand given by the formula;

Annual demand;D = pd

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D = 1707750 hot dogs/yr

Now, formula for optimal run size is given by;

Q_o = √[(2DS/H) × (p/(p - u))]

Plugging in the relevant values gives;

Q_o = √[(2 × 1707750 × 67/0.47) × (5750/(5650 - 270))]

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no. of runs = 1707750/22812

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Length ≈ 4 days in a run

6 0
2 years ago
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