Answer: He has 7 at the moment, technically, if he still has the bag, he still has all 36
Step-by-step explanation:
Answer:
x=4.2
Step-by-step explanation:
29-3=5x+5
21=5x, x=21/5=4.2
Answer:
$4.50
Step-by-step explanation:
11.25 / 2.50 = 4.50
Answer:
Terminal side in 2nd Quadrant
Only sin(x) & cosec(x) are positive in 2nd Quadrant

Perpendicular=5
Base=√(13²-5²)=√(169-25)=√144=√12²=12
Hypotenuse=13

Answer: -3 and 3
Step-by-step explanation: You first find the area of OBA which is 6, then you plot points that make a triangle that is congurent to 6. I fond that since there was a length of 4 in both, I simply went up three on the y-axis and down three on the y-axis. Sorry for the bad explanation but this is all I knew.