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NikAS [45]
3 years ago
5

D%7Bx%C2%B2-4%7D%7D" id="TexFormula1" title="\large\rm{Add\:\frac{x}{x²-4}\:\:and\:\:\frac{2}{x²-4}}" alt="\large\rm{Add\:\frac{x}{x²-4}\:\:and\:\:\frac{2}{x²-4}}" align="absmiddle" class="latex-formula">
\\
What's the answer? ;-;​
Mathematics
2 answers:
Pavel [41]3 years ago
8 0

Answer:

\frac{x}{ {x}^{2} - 4 }  +  \frac{2}{ {x}^{2}  - 4}  \\  =  \frac{x + 2}{ {x}^{2}  - 4}  \\  =  \frac{x  + 2}{(x + 2)(x - 2)}  \\  =  \frac{1}{x - 2}  \\ thank \: you

Svet_ta [14]3 years ago
3 0

Answer:

since the bottoms are the same is should be

x+2/x^2-4

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irakobra [83]

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8x^3-11x+9-7x^2

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4 0
3 years ago
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julsineya [31]

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3 years ago
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