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3 years ago

Please help me on graphing sine and cosine functions!

Mathematics

1 answer:

Katyanochek1 [597]3 years ago

7 0

Answer:

what's the question the pic is not clear

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By coincidence, Kimberly's Paint Supplies sold equal quantities of two paint colors yesterday: yellow and blue. All yellow paint

Vlad1618 [11]

Answer:

36 liters

Step-by-step explanation:

We solve this question using the least common multiple method

Find and list multiples of the liter the blue paint comes in the liters the yellow paint comes in. We find the first common multiple is found. This is the least common multiple.

Multiples of 9:

9, 18, 27, 36, 45, 54

Multiples of 12:

12, 24, 36, 48, 60

Therefore,

LCM(9, 12) = 36

Hence, the smallest amount of each paint color the store must have sold is 36 liters

8 0

3 years ago

Paul started work at company b ten years ago at the salary of 30,000 starting year and 2400 for yearly salary increase at the sa

Cloud [144]

Sharla, earned 2,000 more than Paul

6 0

3 years ago

PLEASE HELP! I GIVE BRAINLIEST!! What are the correct values for the missing boxes in the ratio table in number 4 above?

Alekssandra [29.7K]

I think is C. 1 client and 24 hours

because

12÷3=4

4÷4=1

6×4=24

ratio

client: hours

1 : 4

3 0

3 years ago

Read 2 more answers

Write the next three terms in each sequence. Make sure your

vazorg [7]

Um, wouldn’t it just be 9.5, 10.6, 11.7?

8 0

3 years ago

Read 2 more answers

a tight roll of paper, as delivered to the printer, is 60cm in diameter, and the paper is wound on to a wooden cylinder 8cm in d

Alekssandra [29.7K]

The area of the paper is the amount of space it occupies.

The length of papers around the edge is 1607680 cm

The given parameters are:

$\mathbf{d_1 = 60cm}$

$\mathbf{d_2 = 60cm + 8cm = 68cm}$

The area of the circle head is:

$\mathbf{Area = \pi \frac{d^2}{4}}$

So, we have:

$\mathbf{Area = \pi \frac{d_2^2 - d_1^2}{4}}$

Substitute known values

$\mathbf{Area = \pi \frac{68^2 - 60^2}{4}}$

$\mathbf{Area = \pi \frac{1024}{4}}$

$\mathbf{Area = 256\pi}$

The length of the paper is then calculated as:

$\mathbf{Length = \frac{Area}{0.0005}}$

This gives

$\mathbf{Length = \frac{256\pi}{0.0005}}$

$\mathbf{Length = \frac{256 \times 3.14}{0.0005}}$

$\mathbf{Length = 1607680}$

Hence, the length of papers around the edge is 1607680 cm