Answer:
-x - 3y + z
Step-by-step explanation:
Think of a imaginary 1(-1 because of the sign) in front of the parenthesis and distribute it to the other number and so x will become -x, 3y will become -3y and -z will become z because two negatives make a positive.
Answer:
Step-by-step explanation:
number of cards = 52
number of queen = 4
number of spades = 13
A) probability that the tenth card is a queen
drawn time (r) = 1
position of success(x) = 10th
p = 4/52
P( x,r,p) = 
p(10,1,4/52) = 9C0(4/52)^1 * (48/52)^9 = 0.0374
B) probability the twentieth card is a spade
x = 20
r = 1
p = 13 / 52
P(20,1,26/52) = 19C0(26/52)^1 * (26/52)^19 = 0.0010
c) The last five cards been spades
p(last five cards been spades )
p(48..52, 5, 13/52 ) = 47...52C4(13/52)^5 * (39/52)^48..52 - 5
6-6a=3a-3b+1, 9a-3b=5
<span>4b - 8 =3a, 3a-4b=-8
</span>
9a-3b=5
(3a-4b=-8 )*(-3 )
9a -3b= 5
-9a+12b=+24
adding both equations
9b=29, b=29/9
3a=4b-8=4*29/9 -8=(4*29-8*9)/9 = 44/9
a=44/27
a-b=44/27 - 29/9=44/27 - 29*3/27=-43/27
this is a correct answer, unfortunately they do not have this choice, probably they made mistake somewhere. I even check the solution of equations by substitution values of a and b into equations
Answer:
a) 0.70
b) 0.30
c) 12/45 =4/15
d) 2/45
Step-by-step explanation:
a) Prob of drawing a marble red or white = No of red and white marbles/total marbles
= 7/10 = 0.70
b) Prob of drawing a marble neither red nor white = 1-7/10 = 0.30
c) Prob of drawing two marble one red and one white at the same time
= 
d) Prob of drawing two marble one blue and orange white at the same time
= 