Why not look up "standard deviation" yourself, to be sure? But yes, the std. dev. is the sqrt of the variance.
Answer:
Step-by-step explanation:
(qx^2-5qx-3)÷(x+2) gives remainder 14q-3
Equating remanders 14q-3=4
14q=7
q=1/2
Answer:
x=17
Step-by-step explanation:
So the outside angle is basically is an addition of the two angles given to you. 60°+2x°=94°.
Please note that your x^3/4 is ambiguous. Did you mean (x^3) divided by 4
or did you mean x to the power (3/4)? I will assume you meant the first, not the second. Please use the "^" symbol to denote exponentiation.
If we have a function f(x) and its derivative f'(x), and a particular x value (c) at which to begin, then the linearization of the function f(x) is
f(x) approx. equal to [f '(c)]x + f(c)].
Here a = c = 81.
Thus, the linearization of the given function at a = c = 81 is
f(x) (approx. equal to) 3(81^2)/4 + [81^3]/4
Note that f '(c) is the slope of the line and is equal to (3/4)(81^2), and f(c) is the function value at x=c, or (81^3)/4.
What is the linearization of f(x) = (x^3)/4, if c = a = 81?
It will be f(x) (approx. equal to)
I got D, but it had a decimal at the end between the 2 and the 6.
But i still got D. So D is my answer.
