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SVETLANKA909090 [29]
2 years ago
9

Determine if the lines are parallel perpendicular or neither x-3y=15 and y=-3x+4

Mathematics
1 answer:
geniusboy [140]2 years ago
8 0

Answer: Perpendicular

Step-by-step explanation:

Convert both equations into slope-intercept form

y=-3x+4 ⇒ y=-3x+4

x-3y=15 ⇒ y=\frac{1}{3} x-5

Determine the slope of each equation

y=-3x+4: SLOPE = -3

y=\frac{1}{3} x-5: SLOPE = 1/3

When two lines are parallel to each other, their slopes will be the same. However, since -3 does not equal 1/3, they are <u>not parallel</u>

-3\neq \frac{1}{3}

When two lines are perpendicular to each other, the product of their slopes will be -1. Since -3 multiply by 1/3 is -1, they are <u>perpendicular to each other.</u>

(-3)*(\frac{1}{3} )=-1

Hope this helps!! :)

Please let me know if you have any questions

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Answer:

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cost of the cleaning is calculated from the area of the carpets

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Cost of the cleaning, C is the dependent variable

Area of the carpet, a is the independent variable

A dependent variable is a variable which depends on other factors to exist. They take their values based on other factors. Their value is changed as a result of a change in independent variable

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Which equation represents a line that passes through the two points in the
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Step-by-step explanation:

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3 years ago
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2 years ago
What is the circumference of the circle? Use 3.14 for x
GuDViN [60]

Answer:

C = 6.28r

Step-by-step explanation:

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3 years ago
Solve the system of linear equations.
sweet-ann [11.9K]

Answer:

  • dependent system
  • x = 2 -a
  • y = 1 +a
  • z = a

Step-by-step explanation:

Let's solve this by eliminating z, then we'll go from there.

Add 6 times the second equation to the first.

  (3x -3y +6z) +6(x +2y -z) = (3) +6(4)

  9x +9y = 27 . . . simplify

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Add 13 times the second equation to the third.

  (5x -8y +13z) +13(x +2y -z) = (2) +13(4)

  18x +18y = 54

  x + y = 3 . . . . . . divide by 18 [eq5]

Equations [eq4] and [eq5] are identical. This tells us the system is dependent, and has an infinite number of solutions. We can find them in terms of z:

  y = 3 -x . . . . solve eq5 for y

  x +2(3 -x) -z = 4 . . . . substitute into the second equation

  -x +6 -z = 4

  x = 2 - z . . . . . . add x-4

  y = 3 -(2 -z)

  y = z +1

So far, we have written the solutions in terms of z. If we use the parameter "a", we can write the solutions as ...

  x = 2 -a

  y = 1 +a

  z = a

_____

<em>Check</em>

First equation:

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  6 -3a -3a -3 +6a = 3 . . . true

Second equation:

  (2-a) +2(a+1) -a = 4

  2 -a +2a +2 -a = 4 . . . true

Third equation:

  5(2-a) -8(a+1) +13a = 2

  10 -5a -8a -8 +13a = 2 . . . true

Our solution checks algebraically.

6 0
3 years ago
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