Question

At the end of a recent WNBA regular season, the Phoenix murmur had 12 more victories than losses. The number of victories they had was one more than two times the number of losses. How many regular season games did the Phoenix Mercury play during that season?

Answer 1

Answer:

34 games

Step-by-step explanation:

let the number of losses be  $l$

let the number of victories be  $v$

the Phoenix murmur had 12 more victories than losses:

$v=l+12$

The number of victories they had was one more than two times the number of losses:

$v=2l+1$

We have 2 expressions for $v$, equating these 2, we can solve for $l$:

$l+12=2l+1\\12-1=2l-l\\11=l$

So 11 games, they lost.

Using this value, we can plug into the 1st equation to solve for v:

$v=l+12\\v=11+12\\v=23$

So 23 games, they won.

Given that no draws, they played a total of 23 + 11 = 34 games this season