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satela [25.4K]
3 years ago
8

At the end of a recent WNBA regular season, the Phoenix murmur had 12 more victories than losses. The number of victories they h

ad was one more than two times the number of losses. How many regular season games did the Phoenix Mercury play during that season?
Mathematics
1 answer:
Hoochie [10]3 years ago
6 0

Answer:

34 games


Step-by-step explanation:

let the number of losses be  l

let the number of victories be  v


<u>the Phoenix murmur had 12 more victories than losses:</u>

v=l+12

<u>The number of victories they had was one more than two times the number of losses:</u>

v=2l+1


<em>We have 2 expressions for v, equating these 2, we can solve for l:</em>

l+12=2l+1\\12-1=2l-l\\11=l

So 11 games, they lost.

Using this value, we can plug into the 1st equation to solve for v:

v=l+12\\v=11+12\\v=23

So 23 games, they won.


Given that no draws, they played a total of 23 + 11 = 34 games this season

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<h2><u>QUADRATIC EQUATION</u></h2>

<h2>\mathbb{ANSWER:}</h2>
  • \bold{x = 0.8 \: } \:  \sf \:  {\color{grey}or} \:  \:  \:  \bold{ x=  \frac{4}{5} } \\

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