1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Readme [11.4K]
2 years ago
14

Sum of the exterior angles of a polygon

Mathematics
1 answer:
kykrilka [37]2 years ago
5 0

Answer:

X = 37

Step-by-step explanation:

Polygon = 360 Degrees

(x+9)+(2x)+(x-1)+(3x)+(x)+(x+19)=360 [Solve for x]

You might be interested in
Solve math question of 2 x +8 < 18
Elena-2011 [213]

Answer:

x < 5

Step-by-step explanation:

2 x +8 < 18

Subtract 8 from each side

2x+8-8 < 18 -8

2x< 10

Divide by 2

2x/2 < 10/2

x < 5

8 0
3 years ago
Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 75.6 Mbp
olga55 [171]

Answer:

a) 59.98

b) 2.99

c) 2.99

d) Significantly High

Step-by-step explanation:

Part a)

Highest speed measured = x = 75.6 Mbps

Average/Mean speed = \overline{x} = 15.62 Mbps

Standard Deviation = s = 20.03 Mbps

We need to find the difference between carrier's highest data speed and the mean of all 50 data​ speeds i.e. x - \overline{x}

x - \overline{x} = 75.6 - 15.62 = 59.98 Mbps

Thus, the difference between​ carrier's highest data speed and the mean of all 50 data​ speeds is 59.98 Mbps

Part b)

In order to find how many standard deviations away is the difference found in previous part, we divide the difference by the value of standard deviation i.e.

\frac{59.98}{20.03}=2.99

This means, the difference is 2.99 standard deviations or in other words we can say, the Carrier's highest data speed is 2.99 standard deviations above the mean data speed.

Part c)

A z score tells us that how many standard deviations away is a value from the mean. We calculated the same in the previous part. Performing the same calculation in one step:

The formula for the z score is:

z=\frac{x-\overline{x}}{s}

Using the given values, we get:

z=\frac{75.6-15.62}{20.03}=2.99

Thus, the Carriers highest data is equivalent to a z score of 2.99

Part d)

The range of z scores which are neither significantly low nor significantly​ high is -2 to + 2. The z scores outside this range will be significant.

Since, the z score for carrier's highest data speed is 2.99 which is well outside the given range, i.e. greater than 2, we can conclude that the  carrier's highest data speed​ is significantly higher.

3 0
3 years ago
The diameter of a circle is 5 inches. ​ ​Find the length of its radius.
andreev551 [17]

Answer:

2.5 inches

Step-by-step explanation:

To find the radius when you only have the diameter then you divide the diameter in half and you get your radius

5/2= 2.5

4 0
3 years ago
Simplify ((4x^3)^3 x (4x)^2)^5​
polet [3.4K]

Answer: simplify ((4x^3)^3 x (4x)^2)^5​ = 1125899906842620

Step-by-step explanation: Simplify the expression.

1125899906842620

x

7 0
3 years ago
Use the following information to answer Part A Part B
vekshin1

Answer:

can some one please answer it please

Step-by-step explanation:

8 0
3 years ago
Other questions:
  • Which function is graphed?
    10·1 answer
  • Is (9,9) a solution of the following linear
    6·1 answer
  • Which of these statements are true?
    7·1 answer
  • Which fraction is the smallest? 7/10 2/3 4/5 11/15
    14·2 answers
  • What is the LCM of 2 and 9
    15·2 answers
  • 2) Key components of financial planning include all of the following except:
    11·1 answer
  • Two friends shop for fresh fruit. Jackson buys a watermelon for ​$6.85 and 5 pounds of cherries. Tim buys a pineapple for ​$3.35
    15·1 answer
  • Round 12.5829 to the nearest tenth.
    9·1 answer
  • Help ASAP<br> PLZZZZ!!!
    13·1 answer
  • Peter left city a at 9:00 am towards city b at an average speed of 50 mph. Thirty minutes later Emily also leaves city a towards
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!