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2 years ago

PLEASE HELP ASAP!! :D

Mathematics

1 answer:

MaRussiya [10]2 years ago

4 0

Answer:

x+39°+93°=180°

x+132°=180°

x=180°-132°

x=148°

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Four less than the quotient of a number 2 and 5.

Papessa [141]

Answer:

2/5 - 4

Step-by-step explanation:

quotient means to divide

4 less means subtraction

8 0

2 years ago

Can someone help me please

yuradex [85]

Answer:

Step-by-step explanation:

The angle is the same so they would both be 60 degrees.

6 0

3 years ago

Read 2 more answers

A company uses three different assembly lines- A1, A2, and A3- to manufacture a particular component. Of thosemanufactured by li

hammer [34]

Answer:

The probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

Step-by-step explanation:

The three different assembly lines are: A₁, A₂ and A₃.

Denote <em>R</em> as the event that a component needs rework.

It is given that:

$P (R|A_{1})=0.05\\P (R|A_{2})=0.08\\P (R|A_{3})=0.10\\P (A_{1})=0.50\\P (A_{2})=0.30\\P (A_{3})=0.20$

Compute the probability that a randomly selected component needs rework as follows:

$P(R)=P(R|A_{1})P(A_{1})+P(R|A_{2})P(A_{2})+P(R|A_{3})P(A_{3})\\=(0.05\times0.50)+(0.08\times0.30)+(0.10\times0.20)\\=0.069$

Compute the probability that a randomly selected component needs rework when it came from line A₁ as follows:

$P (A_{1}|R)=\frac{P(R|A_{1})P(A_{1})}{P(R)}=\frac{0.05\times0.50}{0.069} =0.3623$

Thus, the probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

6 0

3 years ago

We have a study involving 5 different groups that each contain 9 participants (45 total). What two degrees of freedom would we r

vivado [14]

Answer:

Degree of freedoms F(4,40)

Step-by-step explanation:

Given:

There is a study which is involving 5 different groups that each contains 9 participants (totally 45)

The objective is to calculate the degree of freedoms

Formula used:

Numerator degree of freedom = k-1

denominator degree of freedom=N-K

Solution:

Numerator degree of freedom = k-1

denominator degree of freedom=N-K

Where,

K= number of groups = 5

N= total number of observations

which is given as follows,

N=45

Then,

Numerator degree of freedom = k-1

=5-1

Denominator degree of freedom = N-K

=45-5

=40

Therefore,

Degree of freedoms, F(4,40)

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2 years ago

WILL GIVE BRAINLY NEED HELP BAD PLZ WUICK <br> What is the perimeter of the triangle?<br> units

AysviL [449]

Answer:

26units!

Step-by-step explanation:

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2 years ago