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victus00 [196]
3 years ago
11

Hello, can anyone help me with this? i need this rn, ( NEED A SOLUTION ) tysm.!

Mathematics
2 answers:
klasskru [66]3 years ago
8 0

Answer:

You want Solution of which question????

blagie [28]3 years ago
7 0

Explanation:

Uhhmmm.....Where is ur Question though?..

We can't even answer it cuz u didn't put any picture or something..

But nxt time,put it a picture so we can answer it clearly..

(;ŏ﹏ŏ)(ㆁωㆁ)

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In 2021, Ryan Management collected rent revenue for 2022 tenant occupancy. For financial reporting, the rent is recorded as defe
Natasha_Volkova [10]

Answer:

Answer and Explanation:

The Journal entry is shown below:-

1. Income Tax Expense Dr, $336 million  

Deferred Tax Assets Dr, $29 million

($116 million  × 25%)

         To Income Tax Payable $365 million

($1,460 × 25%)

(Being income tax and deferred tax is recorded)

2. Income Tax Expense Dr, $400 million

         To Income Tax Payable  $340  million

($1,360 × 25%)

         To Deferred Tax Assets $60 million

(($354.0 million - $116 million)  × 25%)

(Being income tax and deferred tax is recorded)

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Electrical energy (E) is measured in kilowatt hours (kwh) using the formula E = P · t, where P is the power in kilowatts and t i
sveticcg [70]
Kilowatts of power are used each hour
104/13=8
7 0
3 years ago
write equation that has base of 3 stretched vertically by factor of 2/3 reflected in y axis, asymptote of y=2 and passes through
madam [21]

The exponential equation is y = \frac23(3)^{-x+0.74} + 2

<h3>How to determine the equation?</h3>

An exponential function is represented as:

y = b^x

The base is 3.

So, we have:

y = 3^x

It is stretched vertically by 2/3.

So, we have:

y = \frac23(3)^x

When reflected over the y-axis, we have:

y = \frac23(3)^{-x}

An asymptote of y = 2, makes the function becomes

y = \frac23(3)^{-x} + 2

Lastly, it passes through the point (0, 3.5).

So, we have:

y = \frac23(3)^{-x+h} + 2

This gives

3.5 = \frac23(3)^{-0+h} + 2

3.5 = \frac23(3)^{h} + 2

Subtract 2 from both sides

1.5 = \frac23(3)^{h}

Multiply by 3/2

2.25 = (3)^{h}

Take the logarithm of both sides

log(2.25) = h * log(3)

Solve for h

h = 0.74

Substitute h = 0.74 in y = \frac23(3)^{-x+h} + 2

y = \frac23(3)^{-x+0.74} + 2

Hence, the exponential equation is y = \frac23(3)^{-x+0.74} + 2

Read more about exponential equation at

brainly.com/question/23729449

#SPJ1

3 0
2 years ago
Monique said 0.70 is greater than 0.7 because 70 is greater than 7. do you agree with monique
elixir [45]
No. 0.70 is the same as 0.7, for the place value of 7 is the same for both (tenths place). In 0.70, the place value of 0 is the hundredth, which is not needed.


0.70 = 0.7

Disagree is your answer

hope this helps
7 0
3 years ago
Jim had 360 stamps he sold 1/3 of them on Monday and 1/4 of the remainder on Tuesday how many stamps did he sell on Tuesday
denis-greek [22]

Answer:

60

Step-by-step explanation:

Since Jim sold 1/3 of his stamps on Monday, the remainder would be 2/3 of his total stamps.

<em>Divide 360 stamps by 3. Minus the stamps</em><em> </em><em>sold on Monday from 36</em><em>0</em><em> </em><em>to</em><em> </em><em>get</em><em> </em><em>the</em><em> </em><em>remainder</em><em>.</em>

stamps sold on Monday = 360 ÷ 3 = 120

remainder = 360 - 120 = 240

He sold 1/4 of the remainder on Tuesday.

<em>Divide the remainder by 4.</em>

stamps sold on Tuesday = 240 ÷ 4 = 60

<em>He sold 60 stamps on Tuesday</em><em>.</em>

6 0
3 years ago
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