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masha68 [24]
3 years ago
14

Simplify 2k^8×3k^3 ​

Mathematics
2 answers:
KatRina [158]3 years ago
8 0

Answer:

6k^{11}  

I hope this helps!

erik [133]3 years ago
4 0

Answer:

6 k^ 11

Step-by-step explanation:

2k^8×3k^3

2*3  * k^8 * k^3

6 * k^8 * k^3

When multiplying exponents with the same base, we can add the exponents

6 k^( 8+3)

6 k^ 11

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The function y = x 2 - 10x + 31 has a ____
katrin [286]

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Option B. minimum is correct for the first blank

Option C. 6 is correct for second blank.

Step-by-step explanation:

In order to find the maxima or minima of a function, we have to take the first derivative and then put it equal to zero to find the critical values.

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f(x) = x^2-10x+31

Taking first derivative

f'(x) = 2x-10

Now the first derivative has to be put equal to zero to find the critical value

2x-10 = 0\\2x = 10\\x = \frac{10}{2} = 5

The function has only one critical value which is 5.

Taking 2nd derivative

f''(x) =2

f''(5) = 2

As the value of 2nd derivative is positive for the critical value 5, this means that the function has a minimum value at x = 5

The value can be found out by putting x=5 in the function

f(5) = (5)^2-10(5)+31\\=25-50+31\\=6

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<u>The function y = x 2 - 10x + 31 has a minimum  value of 6</u>

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