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3 years ago

If ∆ABC is rotated 90° counterclockwise around the origin, what are the coordinates of the transformed figure ∆A’B’C’ ?

Mathematics

1 answer:

KATRIN_1 [288]3 years ago

4 0

This question can’t be answered without the original coordinates of ABC

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The sum of the measures of angles xand y is 120°. The measure of the angle x is 12 less than the measure of the angle y. Find x

Troyanec [42]

Answer:
x = 54°
y = 66°

Step-by-step explanation:

x + y = 120° (given)
x = y - 12
Then, y + y - 12 = 120°
(y + y) - 12 = 120°
2y - 12 = 120°
2y = 120 + 12 = 132°
y = 132/2 = 66°
x = y - 12 = 66 - 12 = 54°
There you go :)

5 0

2 years ago

Neil put on a blindfold and picked 72 jelly beans from a jar.

Natasha2012 [34]

No because really it’s not explains nothing

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3 years ago

Messy Marvin buys a bag of peanuts and eats 20% of whatever is in the bag each day. If there are 256 peanuts left in the bag aft

scoray [572]

307 peanuts were originally in the bag

6 0

4 years ago

1. A grand tour of four cities begins at city A and makes successive stops at cities B, C,

vampirchik [111]

Using distance between two points, it is found that the total distance covered on the tour is of 3400 miles.

Given two points $(x_1,y_1)$ and $(x_2,y_2)$ , their distance is given by:

$D = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

In this problem, the formula is used to find the distance covered on each tour, hence:

$d_{AB} = \sqrt{(400 - 0)^2 + (300 - 0)^2} = 500$

$d_{BC} = \sqrt{(-800 - 400)^2 + (800 - 300)^2} = 1300$

$d_{CD} = \sqrt{(-800 - (-800))^2 + (0 - 800)^2} = 800$

$d_{DA} = \sqrt{(0 - (-800))^2 + (0 - 0)^2} = 800$

Then, the total distance is given by the sum of each separate distance, hence:

$d = d_{AB} + d_{BC} + d_{CD} + d_{DA} = 500 + 1300 + 800 + 800 = 3400$

The total distance covered on the tour is of 3400 miles.

You can learn more about distance between two points at brainly.com/question/25929988

3 0

2 years ago

Please help me with questions 23-39

Mrac [35]

Answer:

23) 36·(3·1/4) = 36·(3/4) = 108/4 = 27

24) (4·2/7)·21 = (8/7)·21 = 168/7 = 24

25) 2(x+4) = 2x+8

26) (5+n)3 = 15+3n

27) (4-3m)8 = 32-24m

28) -3(2x-6) = -6x+18

29) 13r+5r = 18r

30) 3x³-2x²

31) 7m+7-5m = 2m+7

32) 5z²+3z+8z² = 3z+13z²

33) (2-4n)17 = 34-68n

34) 11(4d+6) = 44d+66

35) 7m+2m+5p+4m = 13m+5p

36) 3x+7(3x+4) = 3x+21x+28 = 24x+28

37) 4(fg+3g)+5g = 4fg+12g+5g = 4fg+17g

38) (5m)²+(m+5)²= 26m²+10m+25

39) 7(a²+b)-4(a²+b) = 3(a²+b) = 3a²+b

7 0

3 years ago