Question

If angle 0 is in quadrant I, what is the value of

Answer 1

Answer:

$the \: answer \: is \: c \: = - \frac{ \sqrt{14} }{5}$

Step-by-step explanation:

$\sin^{2}0 + ( \frac{ \sqrt{11} }{5} ) ^{2} = 1( \sin^{2}0 + \cos^{2} 0 = 1)$

${ \sin }^{2}0 + \frac{11}{25} = 1 \\ { \sin }^{2}0 = \frac{14}{25}$

$\sin0_{1} = - \frac{ \sqrt{14}}{5} while \sin0_{2} = \frac{ \sqrt{14} }{5}$

• Therfore theta is QI
• Therfore sin theta >0
• $therefore \: \sin0 = \frac{ \sqrt{14} }{5}$