Suppose we wish to determine whether or not two given polynomials with complex coefficients have a common root. Given two first-degree polynomials a0 + a1x and b0 + b1x, we seek a single value of x such that
Solving each of these equations for x we get x = -a0/a1 and x = -b0/b1 respectively, so in order for both equations to be satisfied simultaneously we must have a0/a1 = b0/b1, which can also be written as a0b1 - a1b0 = 0. Formally we can regard this system as two linear equations in the two quantities x0 and x1, and write them in matrix form as
Hence a non-trivial solution requires the vanishing of the determinant of the coefficient matrix, which again gives a0b1 - a1b0 = 0.
Now consider two polynomials of degree 2. In this case we seek a single value of x such that
Hope this helped, Hope I did not make it to complated
Please give me Brainliest
Answer:
Może być odpowiedź c ja ne wiem
All the answers with the step of dilations is correct.
So, it should be 1,2,3,5
Answer:
School related questions please
Step-by-step explanation:
And thanks for telling me
<span>Modelling Algebraic expressions can be done through Algebra Tiles, this is done through squares and rectangles both representing variables and numbers. 4+8x and 4(2x+1) is equivalent because of its distributive property, in the second equation 4 is distributed or multiplied to 2x+1 making it 8x+4. To represent this with Algebra tiles, you need to divide the paper into two, draw a vertical line in the middle that represents equal sign and on the first column, you need to draw 4 squares and beside it are 8 thin rectangles and on the second column you need to draw 8 thin rectangles and beside it are 4 squares. If you can picture it out, basically both equations are equivalent.</span><span />
