Answer:
They can make 49 hamburgers
Step-by-step explanation:
A fleet of nine taxis is to be dispatched to three airports in such a way that three go to airport A, five go to airport B, and one goes to airport C. In how many distinct ways can this be accomplished?
2.44) Refer to Exercise 2.43. Assume that taxis are allocated to airports at random.
a) If exactly one of the taxis is in need of repair, what is the probability that it is dispatched to airport C?
b) If exactly three of the taxis are in need of repair, what is the probability that every airport receives one of the taxis requiring repairs?
So, my answer to 2.44a is 1/9. Hopefully this is correct at least :)
For 2.44b, my guess was
(3C1)(1/3)(2/3)2 * (5C1)(1/3)(2/3)4 * 1/3
The solutions manual on chegg (which seems to be riddled with errors) says something completely different. Is my calculation correct?
Answer:
See Explanation
Step-by-step explanation:
Your question is poorly formatted. However, I'm able to deduce that your question involves at least 2 algebraic fractions that needs to be simplified.
So, I'll make use of the following expression:

When you follow the steps I'm about to provide, you'll arrive at the right answer
Required
Determine an equivalent expression

Step 1: Take L.C.M of the denominators

Step 2: Evaluate the fractions

Step 3: Open the brackets at the numerator

Step 4: Collect and evaluate like terms

<em>Follow the above steps, and you'll be able to solve your question.</em>
The answer x = 7 is false here is why.

This further simplifies to solution,

Hope this helps.
r3t40
Answer:
<h2>5 . 8</h2><h2 />
Step-by-step explanation:

I hope i am correct