All categories

2 years ago

Question below..................

Mathematics

1 answer:

morpeh [17]2 years ago

7 0

............ ........... .

You might be interested in

When ava sat down to read her book, she had already read 54 pages. forty-five minutes later, she had read a total of 92 pages. l

SOVA2 [1]

38
54-2=m
m=38
Im not quite sure if this i right

4 0

3 years ago

A bag holds 6 green, 9 red and 4 blue marbles a marble is selected at random what is the probability of not selecting a red marb

Butoxors [25]

Answer:

The probability of not selecting a red marble, P(R)' = 10/19

Step-by-step explanation:

The probability of an event occurring is equal to the number of ways the required event occurs divided by the number of possible outcomes

The number of ways of an event not occurring is 1 less the probability of the event occurring

The number of green marbles in the bag = 6

The number of red marbles in the bag = 9

The number of blue marbles in the bag = 4

The sum of the marbles in the bag, n = 6 + 9 + 4 = 19

The number of ways of selecting a red marble = 9 ways

The probability of selecting a red marble = 9 ways/19 marbles = 9/19

The probability of not selecting a red marble = 1 - 9/19 = 10/19 = $0.\overline{526315789473684210}$

The probability of not selecting a red marble P(R)' = 10/19

5 0

3 years ago

Read 2 more answers

Find the value of x in each case: (See picture)

sergiy2304 [10]

Step-by-step explanation:

180-124=56°

180-56-2x-(180-6x)=0

180-56-2x-180+6x=0

-56+4x=0

4x=56

x=14°

........

2x=28

6x=84

5 0

3 years ago

What is the solution?

elena-s [515]

D- -8 and F- 8 Because 8x8=64

4 0

3 years ago

Read 2 more answers

Create a matrix that is equal to F+G. The first matrix below is named F and the second matrix below is named G. Name the new mat

likoan [24]

F+G:

$F+G=\begin{bmatrix}{-1.8} & {-8.6} & {} \\ {2.85} & {-1.4} & {} \\ {-1.8} & {5.1} & {}\end{bmatrix}+\begin{bmatrix}{1.32} & {-1.9} & {} \\ {2.25} & {0.0} & {} \\ {-6.2} & {1.4} & {}\end{bmatrix}$

Then, add the elements that occupy the same position:

$H=\begin{bmatrix}{-1.8+1.32} & {-8.6+(-1.9)} & {} \\ {2.85+2.25} & {-1.4+0.0} & {} \\ {-1.8+(-6.2)} & {5.1+1.4} & {}\end{bmatrix}$

Solve

$H=\begin{bmatrix}{-0.48} & {-10.5} & {} \\ {5.1} & {-1.4} & {} \\ {-8} & {6.5} & {}\end{bmatrix}$

So, we find the element at address h31:

$H=\begin{bmatrix}{h11} & {h12} & {} \\ {h21} & {h22} & {} \\ {h31} & {h32} & {}\end{bmatrix}$

In this case, position h31 is - 8.0

8 0

1 year ago