For this simulation, there are 5 numbers that we can draw. One of the numbers will result in seeing the groundhog. (1/5 or 0.20) To find the probability that Jay will see the groundhog 4 years in a row, we would use the following equation: 1/5•1/5•1/5•1/5
We would multiply the odds of getting a certain outcome by the number of time we want that outcome.
The odds that Jay will see the groundhog for the next for years is 0.0016, or .16%.
Answer:
m∠3 = 64°
Since angle 2 and 3 seem to be complementary angles, we know that the meaning of complementary angles is to add both angles to 90 degrees.
Subtract 90 by the known value to get the value of ∠3
90 - 26 = 64
Answer:
a. V = (20-x) 
b . 1185.185
Step-by-step explanation:
Given that:
- The height: 20 - x (in )
- Let x be the length of a side of the base of the box (x>0)
a. Write a polynomial function in factored form modeling the volume V of the box.
As we know that, this is a rectangular box has a square base so the Volume of it is:
V = h *
<=> V = (20-x)
b. What is the maximum possible volume of the box?
To maximum the volume of it, we need to use first derivative of the volume.
<=> dV / Dx = -3 + 40x
Let dV / Dx = 0, we have:
-3 + 40x = 0
<=> x = 40/3
=>the height h = 20/3
So the maximum possible volume of the box is:
V = 20/3 * 40/3 *40/3
= 1185.185
2(11 + 3x) = 64
11 + 3x =64/2
11 + 3x = 32
3x = 32 - 11
3x = 21
x = 21/3
x = 7
A.
Answer:
I believe its C
amsc:dherbo00
Step-by-step explanation:
